Question

我正在尝试制作一个简单的消息传递应用程序，并拥有我认为应该可以使用的代码。...

//
//  ViewController.swift
//  messaging test
//
//  Created by 23AthreyaDaniel on 7/5/18.
//  Copyright © 2018 23AthreyaDaniel. All rights reserved.
//

import UIKit
import MessageUI
class ViewController: UIViewController,MFMessageComposeViewControllerDelegate{
    func messageComposeViewController(_ controller: MFMessageComposeViewController, didFinishWith result: MessageComposeResult) {
    }

    @IBAction func send(_ sender: Any) {
        if MFMessageComposeViewController.canSendText(){
            let controller = MFMessageComposeViewController()
            controller.body = "test"
            controller.recipients = ["6507984792"]
            controller.messageComposeDelegate = self
            self.present(controller,animated: true,completion: nil)
        }
        else{
            print("can't send it")
        }
      func  messageComposeViewController(){
            self.dismiss(animated: true, completion: nil)
        }
    }
    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


}

但是，它一直转到else循环并说无法发送消息。代码有什么问题？

Answer 1

尽管我的代码是正确的，但apple不允许在模拟器上执行短信操作，因此我的第一个if语句@IBAction func cancelButtonAtNavigationBar(_ sender: UIBarButtonItem)中的布尔值始终为False。如果我在具有开发人员许可的实际Apple设备上运行了相同的代码，那将奏效。

使用Xcode进行消息传递

1 个答案: