我有一个For循环来查看列,并且需要跳过两列。当我运行此代码时,第二个For循环(使用iCol)不起作用。
当我在循环外进行测试时,循环内的代码可以正常工作。我尝试了不同的选项以将两列从For循环中排除(选择大小写),但没有任何效果。
Dim rng As Range
Dim n As Long
Dim iRow As Long
Dim iCol As Long
Dim NameColNum As Integer
Dim LNameColNum As Integer
Dim DoBColNum As Integer
Dim SColNum As Integer
Dim JColNum As Integer
' Sets data range
Set rng = Range(Range("A1"), Range("A" & Rows.Count).End(xlUp))
NameColNum = Application.Match("First Name", rng.EntireRow(1), 0)
LNameColNum = Application.Match("Last Name", rng.EntireRow(1), 0)
DoBColNum = Application.Match("Birth Date", rng.EntireRow(1), 0)
' For S and J cases
SColNum = Application.Match("Created User ID", rng.EntireRow(1), 0)
JColNum = Application.Match("W Name", rng.EntireRow(1), 0)
For iRow = 2 To rng.Rows.Count
If rng.Cells(iRow, NameColNum) = rng.Cells(iRow + 1, NameColNum) And _
rng.Cells(iRow, LNameColNum) = rng.Cells(iRow + 1, LNameColNum) And _
rng.Cells(iRow, DoBColNum) = rng.Cells(iRow + 1, DoBColNum) Then
If rng.Cells(iRow, SColNum).Value = "STAGE" Then
rng.EntireRow(iRow).Interior.ColorIndex = 3
rng.EntireRow(iRow + 1).Interior.ColorIndex = 3
End If
If rng.Cells(iRow, JColNum) = "Smith" Then
rng.EntireRow(iRow).Interior.ColorIndex = 4
rng.EntireRow(iRow + 1).Interior.ColorIndex = 4
End If
For iCol = DoBColNum + 1 To rng.Columns.Count
If iCol <> SColNum And iCol <> JColNum Then
If rng.Cells(iRow, iCol).Value <> rng.Cells(iRow + 1, iCol).Value And _
rng.EntireRow(iRow).Interior.ColorIndex = -4142 Then
rng.EntireRow(iRow).Interior.ColorIndex = iCol
rng.EntireRow(iRow + 1).Interior.ColorIndex = iCol
End If
End If
Next 'iCol
End If
Next 'iRow
答案 0 :(得分:3)
rng.Columns.Count
始终等于1,因为您将rng
行中的Set
限制为A列。因此,您的第二个循环将永远不会运行(您正在尝试循环4 to 1
等)。
相反,更改Set rng = Range(Range("A1"), Range("A" & Rows.Count).End(xlUp))
以包括您使用的所有列,并从另一行的A列获取最后一行的值。
建议的解决方法:
Dim lastrow As Long
lastrow = Cells(Rows.Count, "A").End(xlUp).Row
' Sets data range
Set rng = Range(Range("A1"), Range("S" & lastrow))