如何解析JSON属性而不显式引用它们？

Question

我正在将某些SQL Server与具有某些属性的JSON对象一起使用。 JSON学生对象看起来像这样：

SET @studentObject= 
    '{
    "Student": {
    "Id":"' + CAST(NEWID() as NVARCHAR(36)) +'",
    "Name": "StudentA",
    "FavoriteSubject": "Math",
    "Grade": 8
    }
}'

我想提取这些属性（Id，Name，FavoriteSubject和Grade），而无需显式引用它们。本质上是@studentObject类型查询的SELECT ALL PROPERTIES。

现在，我有类似的内容，但我正在尝试使此查询更通用：

 SELECT S.Name, S.Address, 
 JSON_VALUE(Value, '$.Student.Id') AS Id,
 JSON_VALUE(Value, '$.Student.Name') AS StudentName,
 JSON_VALUE(Value, '$.Student.FavoriteSubject') AS FavoriteSubject,
 JSON_VALUE(Value, '$.Student.Grade') AS Grade

 FROM School S;

我试图做一个

SELCT S.Name, S.Address, @studentObjects but it was throwing an exception about an incorrect number of values.