Question

如果我有这样的值

 Name varchar(255) = 'A fox Jumped/ in to the water/ and fought with crocodile/ and then went back/ to jungle and slept'

我想使用'/'作为分隔符来提取值。我可以弄清楚如何将这部分 '提取到丛林并睡觉' ，但是我想获得倒数第二个值 '然后去返回' 以及'/' ”之后的整个部分，然后返回丛林并睡觉”

 Expected values: 

 1. 'and then went back'
 2. 'and then went back/ to jungle and slept'

Answer 1

这可以通过将reverse，substring和charindex与cross apply结合使用来完成。使用一系列cross apply找出字符的第一个，第二个（和第n个出现），然后提取所需的子字符串。

select  
 reverse(substring(reverse(str), p1.pos+1, p2.pos-p1.pos-1)) as between_first_sec_from_last
,reverse(substring(reverse(str), 1, p2.pos- 1)) as upto_second_from_last
from (select 'A fox Jumped/ in to the water/ and fought with crocodile/ and then went back/ to jungle and slept' as str) t
  cross apply (select (charindex('/', reverse(str)))) as p1(pos)
  cross apply (select (charindex('/', reverse(str), p1.pos+1))) as p2(pos)

如何根据模式或值的第二次出现获取字符串？

1 个答案: