Question

我在为QR（矩阵）部分计算代码中两个向量的点积时遇到麻烦。我正在尝试用vector01点q [i]的结果，但我不知道我的代码在哪里不正确。任何帮助都将非常感谢。我的预期输出应该是sqrt（2）

def twoNorm(vector):
    '''
    twoNorm takes a vector as it's argument. It then computes the sum of  
    the squares of each element of the vector. It then returns the square 
    root of this sum.
    '''
    # This variable will keep track of the validity of our input.
    inputStatus = True  
    # This for loop will check each element of the vector to see if it's a number. 
    for i in range(len(vector)):  
        if ((type(vector[i]) != int) and (type(vector[i]) != float) and (type(vector[i]) != complex)):
            inputStatus = False
            print("Invalid Input")
            # If the input is valid the function continues to compute the 2-norm
            if inputStatus == True:
                result = 0
                # This for loop will compute the sum of the squares of the elements of the vector. 
                for i in range(len(vector)):
                    result = result + (vector[i]**2)
                result = result**(1/2)
            return result
    vector = [1, 0, 1]
    print(twoNorm(vector))

def QR(matrix):
    if len(matrix) != len(vector):
        print('Invalid')
    else:
        qi = []
        for i in vector:
            qi.append(i/scalar)
        return qi
        if len(qi) != len(vector01):
            print('invalid input')
        else:
            total = 0
            for j in range(len(qi)):
                total += qi[j] * vector01[j]
            return total

vector01 = [2, 1, 0]   
scalar = twoNorm(vector)
vector = [1, 0, 1]
matrix = [[1, 2], [0, 1], [1, 0]]
print(QR(matrix))

Answer 1

twoNorm（）中的两个“ if”结构不正确（也许只是您没有注意到的缩进问题？）。将下面的代码与您的代码进行比较。您会发现问题所在。

def twoNorm(vector):
    '''
    twoNorm takes a vector as it's argument. It then computes the sum of  
    the squares of each element of the vector. It then returns the square 
    root of this sum.
    '''
    # This variable will keep track of the validity of our input.
    inputStatus = True  
    # This for loop will check each element of the vector to see if it's a number. 
    for i in range(len(vector)):  
        if ((type(vector[i]) != int) and (type(vector[i]) != float) and (type(vector[i]) != complex)):
            inputStatus = False
            print("Invalid Input")
            # If the input is valid the function continues to compute the 2-norm
        if inputStatus == True:
            result = 0
            # This for loop will compute the sum of the squares of the elements of the vector. 
            for i in range(len(vector)):
                result = result + (vector[i]**2)
            result = result**(1/2)
            return result

我没有仔细检查QR（），但是我确定这很麻烦-'return qi'之后的任何东西都不会执行。 QR（）是如何工作的？

两个向量python3的点积

1 个答案: