Question

说我有文件列表

public function actionCartBarcode() {
    $request = Yii::$app->request;

    $productCode = $request->getBodyParam('pcode');



    $invoice = Invoice::find()->where(['status' => 1])->one();
    $invoiceId = $invoice->invoice_id;
    $product = AppProduct::find()->where(['product_code' => $productCode])->one();
    $productId = $product->product_id;
    //first see if product exist (change sales to cart after you create the cart table)
    $model = Sales::find()->where(['r_product_id' => $productId])->andWhere(['r_invoice_id' => $invoiceId])->one();
    if ($model) {
        $model->sold_product_qty += 1;
    } else {

        $model = new Sales();
        $model->r_invoice_id = $invoiceId;
        $model->r_product_id = $productId;
        $model->sold_product_qty = 1;
        $model->discount = 0;
        $model->price_per_unit = $product->product_price;
        $model->total_price = $product->product_price;
        $model->profit = $product->product_price - $product->product_cost;
    }
    if ($model->save()) {
        return 1;
    } else {
        VarDumper::dump($productId, 10, true);
        die();
    }
}

以及路径列表

`(`fileA`fileB`fileC;`fileX`fileY)

如何将它们连接起来以产生

`:a/b`:c/d

我通常会使用

`:a/b/fileA`:a/b/fileB`:a/b/fileC`:c/d/fileX`:c/d/fileX

但是在这种情况下，由于`filelist是2d并且长度不匹配，因此会产生

` sv'paths,'filelist

谢谢

Answer 1

您可以使用each-both和each-right的组合：

q)raze{` sv/:(x,/:y)}'[(`:a/b`:c/d ) ;(`fileA`fileB`fileC;`fileX`fileY)]
`:a/b/fileA`:a/b/fileB`:a/b/fileC`:c/d/fileX`:c/d/fileY

每个权限都将文件追加到dir：

q){` sv/:(x,/:y)}[`:a/b;`fileA`fileB`fileC]
`:a/b/fileA`:a/b/fileB`:a/b/fileC

Answer 2

还可以使用内置的.Q.dd

q).Q.dd''[`:a/b`:c/d;(`fileA`fileB`fileC;`fileX`fileY)]
`:a/b/fileA`:a/b/fileB`:a/b/fileC
`:c/d/fileX`:c/d/fileY

从2d列表创建文件路径kdb q

2 个答案: