Question

我有什么办法可以监视本尼扬日志，以确保打印出我期望的内容？

MyFile.js

const bunyan = require('bunyan');
const log = bunyan.createLogger({name: 'FailureAuditService'});

class someClass {
   someFunct() {
     if(x) {
        log.warn('something happened');
     }
   }
}

测试

const service = require(../MyFile);

describe('test something', () => {
    it('Will test the bunyan log', res => {
       let consoleLog = sinon.spy(log, 'createLogger');
       let x = true;

       service.someClass(x).then(res => {
          let expected = 'something happened';
          consoleLog.should.equal(expected);
       });
    });
})

Answer 1

是的，使用Jest很简单：

let spyLogWarn = jest.spyOn(require('bunyan').prototype, 'warn')
// ...
expect(spyLogWarn).toHaveBeenCalled()

Answer 2

我通过以下方法解决了这个问题：

const mockReq = require('mock-require);

...

let infoStub = sinon.stub();
let warnStub = sinon.stub();

logStubs = {
   info: infoStub,
   warn: warnStub
   // any other log methods you wish to use
};

mockReq('bunyan', {
   createLogger() {
      return logStubs;
   }
});

...

然后，我后来使用过mockReq.reRequire（）函数来重置我要模拟的服务的缓存。

要声明日志的实际内容：

let infoLog = infoStub.firstCall.args[0];
let warnLog = warnStub.firstCall.args[0];

有了这个，我可以断言它们等于我的期望。

Answer 3

For Sinon you may write something like:

const bunyan = require('bunyan');


sinon.stub(bunyan.prototype);
// or
sinon.stub(bunyan.prototype, 'fatal');
// or
sinon.stub(bunyan.prototype, 'fatal').callThrough();

And in asserting

sinon.assert.calledOnce(bunyan.prototype.fatal);

监视Bunyan日志-NodeJS

3 个答案: