将MethodCallExpression附加到属性/参数

Question

我有以下MethodCallExpression：

{Party.Any(party => party.Address.Any(address => address.Line1.Contains("Address 1")))}

我需要将其附加到父级“属性/参数”，以便最终的lambda看起来像：

{txliferequest => txliferequest.OLifE.Party.Any(party => party.Address.Any(address => address.Line1.Contains("Address 1")))}

原始的MethodCallExpression被传递到扩展方法中，因此我尝试附加最终的lambda结构。

---

TXLifeRequest

public partial class TXLifeRequest : BaseEntity
{
    public virtual OLifE OLifE { get; set; }

    ...
}

---

OLifE

public partial class OLifE : BaseEntity
{
    public virtual List<Party> Party { get; set; }
        ...
}

---

聚会

public class Party: BaseEntity
{
    public virtual List<Address> Address { get; set; }
    ...
}

我尝试附加的是作为属性访问器，但不确定如何执行此操作。这是我要尝试的：

//{Name = "OLifE" FullName = "IMSParamed.Entities.OLifE"}
Type parentBaseType = parentPropInfo.GetListBaseType();

//{IMSParamed.Entities.OLifE OLifE}
PropertyInfo propInfo = parentBaseType.GetParentMappedPropertyInfo();

//{OLifE}
ParameterExpression parentTypeParam2 = parentPropInfo.Name.ToParameter(parentBaseType);

//{OLifE.Party}
MemberExpression typeProp = type.Name.ToProperty(parentTypeParam2);

//Type lambdaType = typeof(Func<,>).MakeGenericType(type, typeof(bool));

MethodInfo anyMethod = ExpressionBuilder.anyTSource.MakeGenericMethod(type);

//{OLifE.Party.Any(party => party.Address.Any(address => address.Line1.Contains("Address 1")))}
MethodCallExpression any = Expression.Call(anyMethod, typeProp, methodCallExp);