Question

我有一个像这样的熊猫数据框

>>> df
Out[126]: 
      score        id
0  0.999989    654153
1  0.992971    941351
2  0.979518    701608
3  0.972667    564000
4  0.936928    999843

，并想要转换为漂亮（以便写入具有更好可读性的文本文件）

import prettytable as pt
x = pt.PrettyTable()
for col in list(df.columns):
    x.add_column(col,df[col])

然后在函数中，我使用

print(x.get_string())

并得到此错误

File "<ipython-input-130-8db747160a67>", line 5, in <module>
verbose   = True)

File "<ipython-input-129-4e27c067e0b5>", line 104, in lda_save_eval
print(x.get_string())

File "C:\Users\USER\Anaconda3\envs\tensorflow\lib\site-packages\prettytable.py", line 990, in get_string
self._compute_widths(formatted_rows, options)

File "C:\Users\USER\Anaconda3\envs\tensorflow\lib\site-packages\prettytable.py", line 894, in _compute_widths
widths = [_get_size(field)[0] for field in self._field_names]

File "C:\Users\USER\Anaconda3\envs\tensorflow\lib\site-packages\prettytable.py", line 894, in <listcomp>
widths = [_get_size(field)[0] for field in self._field_names]

File "C:\Users\USER\Anaconda3\envs\tensorflow\lib\site-packages\prettytable.py", line 77, in _get_size
lines = text.split("\n")

AttributeError: 'int' object has no attribute 'split'

有任何线索吗？

Answer 1

尝试用print (x.get_string())代替print(x.get_string)

为了改进，请尝试以下方法：为了以更好的可读性写入文本文件，您无需循环使用tabulate，它使您更加灵活。

尝试一下

from tabulate import tabulate
print (tabulate(df,df.columns,tablefmt='psql'))

在tablefmt中，您可以提供许多选项来获取不同的样式。有关更多详细信息，请参阅此link

Python prettytable get_string错误

1 个答案: