我有一个简单的Web售票网，用JSP用SQL编写。
注册过程如下： start.html-> registration.html-> registration.jsp->完成
所以基本上，在我的起始页上，人们可以单击注册，填写详细信息，然后单击按钮，将执行registration.jsp，然后在其中调用mysql.registeruser（user）方法，然后使用我将sql语句写入数据库。完美运行。
现在，我想尝试JOOQ写入数据库。而不是mysql.registeruser（user），我使用JOOQ.registeruser（user）。
我的JOOQ代码如下：
public static void userregistrierenJOOQ2(user user1) {
try {
Connection conn = DriverManager.getConnection(database, username, password);
DSL.using(conn, SQLDialect.MYSQL).insertInto(User.USER)
.set(User.USER.USERNAME, "steven")
.set(User.USER.VORNAME, "steven")
.onConflict().doUpdate()
.set(User.USER.VIPCODE, 8885)
.execute();
} catch (SQLException err) {
System.out.println("Connect nicht möglich");
System.out.println(err);
}
}
但是，当我单击注册按钮时，我收到此错误消息：
org.apache.jasper.JasperException: An exception occurred processing JSP page /login/registrierung.jsp at line 55
52: out.println("Neuer Versuch: " + "<a href='registrierung.html'>Registrierung</a>");
53: } else {
54: // mysql.userregistrieren2(neu);
55: JOOQ.userregistrierenJOOQ2(neu);
56: mysql.vipcodeloeschen(Integer.parseInt(vipcode));
57: out.println("<p>Sie wurden erfolgreich registriert!</p>");
58: out.println("Bitte einloggen: " + "<a href='start.html'>Einloggen</a>");
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:584)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:466)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:385)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:329)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
root cause
javax.servlet.ServletException: java.lang.NoClassDefFoundError: org/jooq/Table
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:909)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:838)
org.apache.jsp.login.registrierung_jsp._jspService(registrierung_jsp.java:185)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:443)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:385)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:329)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
root cause
java.lang.NoClassDefFoundError: org/jooq/Table
org.apache.jsp.login.registrierung_jsp._jspService(registrierung_jsp.java:158)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:443)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:385)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:329)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
root cause
java.lang.ClassNotFoundException: org.jooq.Table
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1284)
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1118)
org.apache.jsp.login.registrierung_jsp._jspService(registrierung_jsp.java:158)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:443)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:385)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:329)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
我不能从JSP使用JOOQ吗？ 预先感谢！