我需要使用Serilog.Exceptions包来捕获异常。 Serilog从appsettings.json中读取
{
"Serilog": {
"Using": [
"Serilog.Sinks.RollingFile",
"Serilog.Sinks.Seq"
],
"WriteTo": [
{
"Name": "RollingFile",
"Args": {
"restrictedToMinimumLevel": "Debug",
"pathFormat": "myPath\\log-{Date}.log"
}
},
{
"Name": "RollingFile",
"Args": {
"restrictedToMinimumLevel": "Error",
"pathFormat": "myPath\\error-{Date}.log"
}
},
{
"Name": "Seq",
"Args": {
"serverUrl": "myUrl",
"apiKey": "myApiKey"
}
}
],
"Enrich": [
"FromLogContext",
"WithMachineName",
"WithThreadId"
],
"Properties": {
"Application": "myApplicationName"
}
}
}
在我的 startup.cs
中var logger = new LoggerConfiguration()
.Enrich.WithExceptionDetails()
.ReadFrom.Configuration(Configuration)
.CreateLogger();
Log.Logger = logger;
但是它不起作用。我是否需要在appsettings.json中为Serilog.Exceptions包添加其他属性?还是appsettings.json配置正确?我究竟做错了什么? 谢谢
答案 0 :(得分:1)
以下是我在Serilog
中设置ASP.NET Core 2.1
的方式。您可以将其作为清单,看看错过了什么。
Serilog.AspNetCore
,Serilog.Exceptions
,Serilog.Settings.Configuration
和您要使用的其他接收器。在主程序中设置Serilog
:
public class Program
{
public static void Main(string[] args)
{
CreateWebHostBuilder(args).Build().Run();
}
public static IWebHostBuilder CreateWebHostBuilder(string[] args) =>
WebHost.CreateDefaultBuilder(args)
.UseStartup<Startup>()
.UseSerilog((hostingContext, loggerConfiguration) =>
loggerConfiguration
.ReadFrom.Configuration(hostingContext.Configuration)
);
}
将WithExceptionDetails
放在Serilog
的{{1}}部分中:
appsettings.json