这是我的代码。我对如何获取所有记录以及连接两个表的最佳方法有什么想法。 i want adda name here but they print all the data of adda and not same as id of adda_ref in users
created: function () {
let self = this;
const db = firebase.database();
self.userRef = db.ref('/users');
self.addaListRef = db.ref('/adda_list');
self.userRef.orderByChild('type').equalTo('driver').once('value', function (snap) {
self.addaListRef.orderByChild('place_name').once('value', function (addasnap) {
let addadata = addasnap.val();
let renderData = snap.val();
self.data1 = [];
if (renderData !== null) {
let renderDataKeys = Object.keys(renderData);
let addaDataKeys = Object.keys(addadata);
let process_item = 0;
let grabData = [];
let grabData2 = [];
renderDataKeys.forEach(function (val) {
let item = renderData[val];
let item2 = addadata[addaDataKeys[process_item]];
item['key'] = val;
item['time'] = "";
var bar = Object.keys(item).length;
var percent = (bar * 100) / 20;
self.progressValue[process_item] = percent;
if (val.length === 20) {
item['time'] = func.set_date_ser(new Date(func.decode_key(val)));
} else if (item.hasOwnProperty("createdAt")) {
item['time'] = moment(item.createdAt).format("hh:mm A DD/MM/YYYY");
}
grabData.push(item);
grabData2.push(item2);
process_item++;
if (process_item === renderDataKeys.length) {
self.data1['renderData'] = grabData;
self.data1['addadata'] = grabData2;
self.dataLoad = false;
}
});
}
});
});
},