Question

尝试找到未提交特定报告的指导者 - 受指导者组（报告= 147）。所有对都提交了报告，但我还需要那些尚未提交报告的人。

由于

SELECT DISTINCT
     e2.Firstname Mentor_FN
    ,e2.lastname Mentor_LN
    ,e1.Firstname Mentee_FN
    ,e1.lastname Mentee_LN
    ,r.ReportID
FROM
MentorRelationshipStaging m
INNER JOIN Employee e1
    ON e1.EmployeeCode = m.MenteeCode
INNER JOIN Employee e2
    ON e2.EmployeeCode = m.MentorCode
INNER JOIN UserReport ur1 
    ON ur1.EmployeeID = e2.EmployeeID
INNER JOIN Report r 
    ON r.reportID = ur1.ReportID

DATABASE：https://imgur.com/a/9JMRpFw

Answer 1

SELECT DISTINCT
     e2.Firstname Mentor_FN
    ,e2.lastname Mentor_LN
    ,e1.Firstname Mentee_FN
    ,e1.lastname Mentee_LN
    ,r.ReportID
FROM
MentorRelationshipStaging m
INNER JOIN Employee e1
    ON e1.EmployeeCode = m.MenteeCode
INNER JOIN Employee e2
    ON e2.EmployeeCode = m.MentorCode
INNER JOIN UserReport ur1 
    ON ur1.EmployeeID = e2.EmployeeID
INNER JOIN Report r 
    ON r.reportID = ur1.ReportID and ur1.ReportID=147

Answer 2

我不能更具体，因为我们不了解您的架构。但通常使用条件GROUP BY

解决HAVING和COUNT问题

 GROUP BY e2.Firstname
         ,e2.lastname
         ,e1.Firstname
         ,e1.lastname
 HAVING COUNT(CASE WHEN reported = 147 THEN 1 END) = 0

Answer 3

我建议：

SELECT e2.Firstname Mentor_FN, e2.lastname Mentor_LN, e1.Firstname Mentee_FN, e1.lastname Mentee_LN
FROM MentorRelationshipStaging m INNER JOIN
     Employee e1
     ON e1.EmployeeCode = m.MenteeCode INNER JOIN
     Employee e2
     ON e2.EmployeeCode = m.MentorCode LEFT JOIN
     UserReport ur1
     ON ur.EmployeeID = e2.EmployeeID
GROUP BY e2.Firstname Mentor_FN, e2.lastname Mentor_LN, e1.Firstname Mentee_FN, e1.lastname Mentee_LN
HAVING SUM(CASE WHEN ur.ReportId = 147 THEN 1 ELSE 0 END) = 0 ;

或者，如果您不想使用GROUP BY：

SELECT e2.Firstname Mentor_FN, e2.lastname Mentor_LN, e1.Firstname Mentee_FN, e1.lastname Mentee_LN
FROM MentorRelationshipStaging m INNER JOIN
     Employee e1
     ON e1.EmployeeCode = m.MenteeCode INNER JOIN
     Employee e2
     ON e2.EmployeeCode = m.MentorCode LEFT JOIN
     UserReport ur1
     ON ur.EmployeeID = e2.EmployeeID AND ur.ReportId = 147
WHERE ur.EmployeeId IS NULL;

注意：

关键是LEFT JOIN，以确保您获得未提交报告的人。
不需要Reports表格，因为ReportId位于UserReport。
我对JOIN到UserReport有点怀疑。您建议“导师”始终提交报告。

试图找到尚未提交某个报告的Mentor / mentee对

3 个答案: