Question

我正在尝试在Telegram中发布自动时间表。它首先运行，但在尝试循环后我得到一个错误：

TypeError：第一个参数必须是可调用的

我的代码：

import time
import schedule
from pyrogram import Client, ReplyKeyboardMarkup, InlineKeyboardMarkup, InlineKeyboardButton
from pyrogram.api import functions, types
from pyrogram.api.errors import FloodWait


person1 = Client(
    session_name="*cenzored*",
    api_id=*cenzored*,
    api_hash="*cenzored*"
)

person2 = Client(
    session_name="*cenzored*",
    api_id=*cenzored*,
    api_hash="*cenzored*"
)
wick.start()

def Publish(session,dat,msgid,session_name):
    try:
        session.start()
        print("[%s]Posting..." % (session_name))
        session.send(
            functions.messages.GetBotCallbackAnswer(
                peer=session.resolve_peer("*cenzored*"),         
                msg_id=msgid,
                data=b'publish %d' % (dat)
            )
        )
        session.idle()
    except:
        print("Crashed,starting over")

schedule.every(0.3).minutes.do(Publish(person1,142129,12758, 'Dani')) // Here is the line is crashing.
schedule.every(0.3).minutes.do(Publish(person2,137351,13177, 'Wick'))

while 1:
    schedule.run_pending()
    time.sleep(1)

追溯：

Pyrogram v0.7.4, Copyright (C) 2017-2018 Dan Tès <https://github.com/delivrance>
Licensed under the terms of the GNU Lesser General Public License v3 or later (LGPLv3+)

[person1]Posting...
3: 2018-06-16 12:07:26.529829 Retrying <class 'pyrogram.api.functions.messages.get_bot_callback_answer.GetBotCallbackAnswer'>
4: 2018-06-16 12:07:42.041309 Retrying <class 'pyrogram.api.functions.messages.get_bot_callback_answer.GetBotCallbackAnswer'>
Crashed,starting over
Traceback (most recent call last):
  File "C:\Users\343df\OneDrive\Desktop\Maor\python\tele\tele.py", line 35, in <module>
    schedule.every(0.3).minutes.do(Publish('ss',dani,140129,12758, 'Dani'))
  File "C:\Program Files (x86)\Python36-32\lib\site-packages\schedule\__init__.py", line 385, in do
    self.job_func = functools.partial(job_func, *args, **kwargs)
TypeError: the first argument must be callable

基本上我的问题是第一次没有运行（TypeError: the first argument must be callable）并且计划每0.3秒运行一次。

Answer 1

根据[ReadTheDocs]: do(job_func, *args, **kwargs)，您不必调用发布，但只需传递它，然后是其参数列表（将执行调用）通过 schedule 框架）：

schedule.every(0.3).minutes.do(Publish, person1, 142129, 12758, "Dani")
schedule.every(0.3).minutes.do(Publish, person2, 137351, 13177, "Wick")

Answer 2

.do() expects一个可调用的第一个参数（.do的其他参数将被传递给该可调用的。）

所以而不是：

schedule.every(0.3).minutes.do(Publish(person1,142129,12758, 'Dani'))
schedule.every(0.3).minutes.do(Publish(person2,137351,13177, 'Wick'))

你可能想要：

schedule.every(0.3).minutes.do(Publish, person1, 142129, 12758, 'Dani')
schedule.every(0.3).minutes.do(Publish, person2, 137351, 13177, 'Wick')

Telegram TypeError：第一个参数必须是可调用的

2 个答案: