Question

当我从bazel genrule运行一个使用'sh'模块的python脚本时，它失败了：

INFO: Analysed target //src:foo_gen (8 packages loaded).
INFO: Found 1 target...
ERROR: /home/libin11/workspace/test/test/src/BUILD:1:1: Executing genrule //src:foo_gen failed (Exit 1)
Traceback (most recent call last):
  File "src/test.py", line 2, in <module>
    sh.touch("foo.bar")
  File "/usr/local/lib/python2.7/dist-packages/sh.py", line 1427, in __call__
    return RunningCommand(cmd, call_args, stdin, stdout, stderr)
  File "/usr/local/lib/python2.7/dist-packages/sh.py", line 767, in __init__
    self.call_args, pipe, process_assign_lock)
  File "/usr/local/lib/python2.7/dist-packages/sh.py", line 1784, in __init__
    self._stdout_read_fd, self._stdout_write_fd = pty.openpty()
  File "/usr/lib/python2.7/pty.py", line 29, in openpty
    master_fd, slave_name = _open_terminal()
  File "/usr/lib/python2.7/pty.py", line 70, in _open_terminal
    raise os.error, 'out of pty devices'
OSError: out of pty devices
Target //src:foo_gen failed to build
Use --verbose_failures to see the command lines of failed build steps.
INFO: Elapsed time: 2.143s, Critical Path: 0.12s
INFO: 0 processes.
FAILED: Build did NOT complete successfully

我想将第三方项目集成到我自己的项目中。第三方项目是用python脚本构建的，所以我想用bazel genrule构建项目。

以下是一个示例文件列表：

.
├── src
│   ├── BUILD
│   └── test.py
└── WORKSPACE

WORKSPACE为空，BUILD为：

genrule(
    name = "foo_gen",
    srcs = glob(["**/*"]),
    outs = ["foo.bar"],
    cmd = "python $(location test.py)",
)

test.py是：

import sh
sh.touch("foo.bar")

并运行：

bazel build //src:foo_gen

操作系统：Ubuntu 16.04 bazel：发布0.14.1

Answer 1

看起来如果您将呼叫更改为sh.touch("foo.bar", _tty_in=False, _tty_out=False)它可以正常工作，但您仍然需要对该规则进行一些修改，否则它将无法产生输出。

我更喜欢使用bazel python rules导入pip依赖项，因此我可以为我的genrule创建工具。这样，bazel处理pip需求安装，你不必chmod test.py文件。

load("@my_deps//:requirements.bzl", "requirement")

py_binary(
    name = "foo_tool",
    srcs = [
        "test.py",
    ],
    main = "test.py",
    deps = [
        requirement("sh"),
    ],
)

genrule(
    name = "foo_gen",
    outs = ["foo.bar"],
    cmd = """
      python3 $(location //src:foo_tool)
      cp foo.bar $@
    """,
    tools = [":foo_tool"],
)

请注意genrule命令中的所需副本。如果您的python脚本可以输出到标准输出，那么它会更清洁，那么您只需将输出重定向到文件而不是添加复制命令。有关详细信息，请参阅this。

我的输出有这些变化：

INFO: Analysed target //src:foo_gen (0 packages loaded).
INFO: Found 1 target...
Target //src:foo_gen up-to-date:
  bazel-genfiles/src/foo.bar
INFO: Elapsed time: 0.302s, Critical Path: 0.00s
INFO: 0 processes.
INFO: Build completed successfully, 1 total action

不能在Bazel genrule中使用Python的sh模块

1 个答案: