例如我有下表:
---------------------
| amount | date |
---------------------
| 50 | Day 1 |
| 60 | day 2 |
| 20 | day 3 |
| 25 | day 3 |
| 23 | day 4 |
| 26 | day 4 |
| 15 | day 5 |
---------------------
我基本上想要做的是从最近2天检索项目并按最大金额订购该行。所以结果就像:
---------------------
| amount | date |
---------------------
| 26 | day 4 |
| 23 | day 4 |
| 15 | day 5 |
---------------------
仅供参考:上面的2018-06-10 14:37:44
模式输入日期只是一个例子
我试过了:SELECT AMOUNT FROM table WHERE AMOUNT=(SELECT MAX(AMOUNT) FROM table) ORDER BY DATE;
但我获得的结果仅为| 60 | day 2 |
,这是最高金额,而不是最近2个日期;
答案 0 :(得分:0)
试试这个:
SELECT amount, date FROM table WHERE date >= DATE_ADD(CURDATE(), INTERVAL -2 DAY) ORDER BY amount DESC;
-- date > DATE_ADD(CURDATE(), INTERVAL -2 DAY) will give you all rows within 2 days
-- ORDER BY amount DESC will give you ordered by amount descending
答案 1 :(得分:0)