Question

您好，我已经编写了一个代码，可以从Fred获取财务数据。它应该获取所有数据并将数据放入空矩阵中。

这似乎比我想象的更难。例如：

"number of items to replace is not a multiple of replacement length"

但由于TB3MS比其他两组短，我得到一个错误。

cbind.fill <- function(...){
    nm = list(...) 
    nm = lapply(nm, as.matrix)
    n = max(sapply(nm, nrow)) 
    do.call(cbind, lapply(nm, function (x) 
        rbind(x, matrix(, n-nrow(x), ncol(x))))) 
}

我想弄清楚如何解决这个问题？在for循环中创建一个for循环？

我也试过这个：

diff --git a/Formula/readline.rb b/Formula/readline.rb
index 08d3728..d67e5e4 100644
--- a/Formula/readline.rb
+++ b/Formula/readline.rb
@@ -16,7 +16,7 @@ class Readline < Formula
     sha256 "c129333634dd00ab2267ae9c531fca1f5cc50dd519ed3399918289fdfdf2663b" => :lion
   end

-  keg_only :shadowed_by_osx, <<-EOS.undent
+  keg_only :shadowed_by_macos, <<~EOS
     OS X provides the BSD libedit library, which shadows libreadline.
     In order to prevent conflicts when programs look for libreadline we are
     defaulting this GNU Readline installation to keg-only.

但是这个在结尾处给出NA我从头开始需要NA然后用数据填充它。

用不同长度的数据填充空矩阵

0 个答案: