Question

我在上面的例子中复制了我的代码，我的期望是得到一个操作：

[{"data":[{"val":1}]},{"data":[{"val":2}]}]

但我的结果是

[{"data":[{"val":2}]},{"data":[{"val":2}]}]

我不明白为什么请帮助我深入了解这个问题

Answer 1

不确定你想要在那里实现什么，但根据序列，你需要在push时复制对象：

_.forEach([{a:1},{a:2}],function(acombination){
        console.log("acombination",acombination);
        _.find([1,2], function(aheader, headerindex) {
            /*Only for repeat the value*/
                if (aheader == 1) {
                    for (let i = 0; i < 2; i++) {
                      clonedData.data[headerindex].val = acombination.a;
                    }
                }
        });
        var newObj = {};
        newObj = clonedData;
        dataObj.push(JSON.parse(JSON.stringify(newObj))); 
       // I stringified and parsed to create a new copy. You were pushing the object and later changing the same object, which changed both the values.
});
console.log("Ss",JSON.stringify(dataObj))

Answer 2

对这个问题有点不确定，但你可以尝试深度克隆＆＃34; clonedData＆＃34;在推入dataObj数组之前应该解决输出问题。我认为JS是通过引用分配的。

而不是

var newObj = {};
newObj = clonedData;
dataObj.push(newObj);

使用

var newObj = JSON.parse(JSON.stringify(clonedData));
dataObj.push(newObj);

按下时覆盖该值

2 个答案: