Question

我试图用这个情节创建一个动画，随着'beta'的增加，曲线会拉伸，但我不能。拜托，有人可以帮助我吗？

import numpy as np
import matplotlib.pyplot as plt
from matplotlib.animation import FuncAnimation 

# Data:
mu = 1
e = 1
a = 1
c = 1
beta = np.linspace(0.0 ,0.5,25)
C = (mu*((e*a)**2)) / (16*(np.pi**2)*c) 

theta = np.linspace(-2 * np.pi, 2 * np.pi, 200)

fig = plt.figure(figsize=(6,6))
ax = plt.subplot(111, polar=True)

for i in range(len(beta)):
    b = beta[i]
    r = ((np.sin(theta))**2) / ((1 - b*np.cos(theta))**5)
    dP = C*r
    ax.plot(theta, dP)
    ax.set_yticklabels([])
    if i==10000:
        break

plt.show()

Answer 1

您必须创建一个负责更新图表的函数，在这种情况下，我将其称为update()，如下所示：

import numpy as np
import matplotlib.pyplot as plt
from matplotlib.animation import FuncAnimation 

# Data:
mu = 1
e = 1
a = 1
c = 1

beta = np.linspace(0.0 ,0.5,25)
C = (mu*((e*a)**2)) / (16*(np.pi**2)*c) 

theta = np.linspace(-2 * np.pi, 2 * np.pi, 200)

fig = plt.figure(figsize=(6,6))
ax = plt.subplot(111, polar=True)

line, = ax.plot([],[])


def update(b):
    r = (np.sin(theta)**2)/(1 - b*np.cos(theta))**5
    dP = C*r
    line.set_xdata(theta)
    line.set_ydata(dP)
    return line,

ani = FuncAnimation(fig, update, frames=beta, blit=True)
plt.show()

Python动画极地情节

1 个答案: