我正在尝试使用https://stackoverflow.com/a/10693789/1992004中提供的一种VBA宏获得所有可能的组合,但会收到错误For without Next
。我将来自另一个线程的源与我的比较,但没有发现这种差异,这可能导致此错误。
你看,导致这个错误的原因是什么? - 请指点我。我的守则如下。
Option Explicit
Sub Sample()
Dim l As Long, m As Long, n As Long, o As Long, p As Long, q As Long, r As Long, s As Long, t As Long, u As Long
Dim CountComb As Long, lastrow As Long
Range("L2").Value = Now
Application.ScreenUpdating = False
CountComb = 0: lastrow = 18
For l = 1 To 1: For m = 1 To 2
For n = 1 To 2: For o = 1 To 18
For p = 1 To 15: For q = 1 To 10
For r = 1 To 10: For s = 1 To 17
For t = 1 To 3: For u = 1 To 3
Range("L" & lastrow).Value = Range("A" & l).Value & "/" & _
Range("B" & m).Value & "/" & _
Range("C" & n).Value & "/" & _
Range("D" & o).Value & "/" & _
Range("E" & p).Value & "/" & _
Range("F" & q).Value & "/" & _
Range("G" & r).Value & "/" & _
Range("H" & s).Value & "/" & _
Range("I" & t).Value & "/" & _
Range("J" & u).Value
lastrow = lastrow + 1
CountComb = CountComb + 1
Next: Next
Next: Next
Range("L1").Value = CountComb
Range("L3").Value = Now
Application.ScreenUpdating = True
End Sub
答案 0 :(得分:4)
上面的所有评论都解释了你的问题,但这就是你的代码在适当的缩进和缺失的" next"之后的样子。语句:
For l = 1 To 1
For m = 1 To 2
For n = 1 To 2
For o = 1 To 18
For p = 1 To 15
For q = 1 To 10
For r = 1 To 10
For s = 1 To 17
For t = 1 To 3
For u = 1 To 3
Range("L" & lastrow).Value = Range("A" & l).Value & "/" & _
Range("B" & m).Value & "/" & _
Range("C" & n).Value & "/" & _
Range("D" & o).Value & "/" & _
Range("E" & p).Value & "/" & _
Range("F" & q).Value & "/" & _
Range("G" & r).Value & "/" & _
Range("H" & s).Value & "/" & _
Range("I" & t).Value & "/" & _
Range("J" & u).Value
lastrow = lastrow + 1
CountComb = CountComb + 1
Next
Next
Next
Next
Next
Next
Next
Next
Next
Next
至少,它会立即显示代码失败的地方。