Question

我已经阅读了所有Yii2 Framework文档，但在尝试实现它时会让人感到困惑。

我有一个Customer视图，其中显示了customer表中的所有字段，包括地址表中的address_id字段。

我想在Yii2 Framework中使用MySQL实现连接查询，但生成的代码如下：

模特中的CustomerSearch：

class CustomerSearch extends Customer{
/**
 * {@inheritdoc}
 */
public function rules()
{
    return [
        [['customer_id', 'store_id', 'address_id', 'active'], 'integer'],
        [['first_name', 'last_name', 'email', 'create_date', 'last_update'], 'safe'],
    ];
}

/**
 * {@inheritdoc}
 */
public function scenarios()
{
    // bypass scenarios() implementation in the parent class
    return Model::scenarios();
}

/**
 * Creates data provider instance with search query applied
 *
 * @param array $params
 *
 * @return ActiveDataProvider
 */
public function search($params)
{
    $query = Customer::find();

    // add conditions that should always apply here

    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    $this->load($params);

    if (!$this->validate()) {
        // uncomment the following line if you do not want to return any records when validation fails
        // $query->where('0=1');
        return $dataProvider;
    }

    // grid filtering conditions
    $query->andFilterWhere([
        'customer_id' => $this->customer_id,
        'store_id' => $this->store_id,
        'address_id' => $this->address_id,
        'active' => $this->active,
        'create_date' => $this->create_date,
        'last_update' => $this->last_update,
    ]);

    $query->andFilterWhere(['like', 'first_name', $this->first_name])
        ->andFilterWhere(['like', 'last_name', $this->last_name])
        ->andFilterWhere(['like', 'email', $this->email]);

    return $dataProvider;
}

客户类：

class Customer extends \yii\db\ActiveRecord{
/**
 * {@inheritdoc}
 */
public static function tableName()
{
    return 'customer';
}

/**
 * {@inheritdoc}
 */
public function rules()
{
    return [
        [['store_id', 'first_name', 'last_name', 'address_id'], 'required'],
        [['store_id', 'address_id', 'active'], 'integer'],
        [['create_date', 'last_update'], 'safe'],
        [['first_name', 'last_name'], 'string', 'max' => 45],
        [['email'], 'string', 'max' => 50],
    ];
}

/**
 * {@inheritdoc}
 */
public function attributeLabels()
{
    return [
        'customer_id' => 'Customer ID',
        'store_id' => 'Store ID',
        'first_name' => 'First Name',
        'last_name' => 'Last Name',
        'email' => 'Email',
        'address_id' => 'Address ID',
        'active' => 'Active',
        'create_date' => 'Create Date',
        'last_update' => 'Last Update',
    ];
}
}

Answer 1

您需要在ActiveRecord模型中声明一些关系......

请参阅Working with Relational Data

的官方文档

如果您将address_id存储在customer表格中，那么您将与每个拥有1个单address（即一对一关系）的客户联系在一起，这是一个相当糟糕的设计。或者您可以使用junction table。最好将customer_id存储在每个地址记录中并定义一对多关系，使每个客户能够存储多个地址（更像现实生活中的地址，即家庭，工作地址等）。

例如，在您的Customer模型中，您将为客户地址定义has-many关系：

use app\models\Address;

class Customer extends \yii\db\ActiveRecord
{

    /**
     * {@inheritdoc}
     */
    public static function tableName()
    {
        return 'customer';
    }

    /**
     * {@inheritdoc}
     */
    public function rules()
    {
        return [
            [['store_id', 'first_name', 'last_name', 'primary_address_id'], 'required'],
            [['store_id', 'primary_address_id', 'active'], 'integer'],
            [['create_date', 'last_update'], 'safe'],
            [['first_name', 'last_name'], 'string', 'max' => 45],
            [['email'], 'string', 'max' => 50],
        ];
    }

    /**
     * {@inheritdoc}
     */
    public function attributeLabels()
    {
        return [
            'customer_id' => 'Customer ID',
            'store_id' => 'Store ID',
            'first_name' => 'First Name',
            'last_name' => 'Last Name',
            'email' => 'Email',
            'primary_address_id' => 'Primary Address ID',
            'active' => 'Active',
            'create_date' => 'Create Date',
            'last_update' => 'Last Update',
        ];
    }

    /**
     * @return \yii\db\ActiveQuery
     */
    public function getAddresses()
    {
        return $this->hasMany(Address::className(), ['customer_id' => 'id']);
    }

}

在您的Address模型中，您将定义反has-one关系：

    /**
     * @return \yii\db\ActiveQuery
     */
    public function getCustomer()
    {
        return $this->hasOne(Customer::className(), ['id' => 'customer_id']);
    }

然后，您可以通过定义的关系名称从模型实例Access relational data，例如：

// SELECT * FROM `customer` WHERE `id` = 123
$customer = Customer::findOne(123);

// SELECT * FROM `address` WHERE `customer_id` = 123
// $addresses is an array of Address objects
$addresses = $customer->addresses;

另请注意，如果在架构中定义正确的主键/外键，Gii Model / CRUD生成器将自动在模型和CRUD文件中创建样板关系代码。

如何在Yii2中实现连接查询

1 个答案: