如何回调超级类Scala

Question

我有两个特点：

trait ThingA[B, A <: OtherThingA[B]] extends ExtendedThing[B, A] {
  def ImportantButNotSharedLogicThing =
    "Something different"
}

trait ThingB[B, A <: OtherThingA[B]] extends ExtendedThing[B, A] {
  def ImportantButNotSharedLogicThing =
    "Something different again"
}

和ExtendedThing

中的此方法

trait ExtendedThing[B, A <: OtherThing[B]] {
   <lots of shared logic>

   <even more shared logic>
    def apply(): A = 
       ImportantButNotSharedLogicThing()
}

如果我有一个扩展ThingA的对象

object Someobject extends ThingA

，apply

最终会调用SmartsOrderWriter()方法

从ExtendedThing特征，我如何调用ThingA或ThingB中定义的方法（对于扩展ThingB的对象