我正在尝试创建一个类型,它可以作为任意其他类型的包装器,因此我可以创建一个异构数组,因为它在Heterogeneous array of Fortran classes和Creating heterogeneous arrays in Fortran中被建议。
所以,我试图像这样实现它:
module m
implicit none
type :: container
class(*), pointer, public :: item
end type container
end module m
program mwe
use m
implicit none
type(container) :: cont
integer, target :: i
i = 5
cont = container(i)
write(*,*) cont%item
end program mwe
现在我收到了错误
test4.f90(20): error #5513: A polymorphic I/O list item requires a user-defined derived-type input/output procedure.
write(*,*) cont%item
----^
compilation aborted for test4.f90 (code 1)
所以我尝试像这样实现I / O:
module m
implicit none
type :: container
class(*), pointer, public :: item
contains
procedure :: write_sample => write_container_sample_impl
procedure :: read_sample => read_container_sample_impl
generic :: write(unformatted) => write_sample
generic :: read(unformatted) => read_sample
end type container
contains
subroutine write_container_sample_impl(this, unit, iostat, iomsg)
class(container), intent(in) :: this
integer, intent(in) :: unit
integer, intent(out) :: iostat
character(*), intent(inout) :: iomsg
write(unit, iostat=iostat, iomsg=iomsg) this%item
end subroutine write_container_sample_impl
subroutine read_container_sample_impl(this, unit, iostat, iomsg)
class(container), intent(inout) :: this
integer, intent(in) :: unit
integer, intent(out) :: iostat
character(*), intent(inout) :: iomsg
read(unit, iostat=iostat, iomsg=iomsg) this%item
end subroutine read_container_sample_impl
end module m
program mwe
use m
implicit none
type(container) :: cont
integer, target :: i
i = 5
cont = container(i)
write(*,*) cont%item
end program mwe
但即使在我的新方法中也会出现同样的错误:
test4.f90(22): error #5513: A polymorphic I/O list item requires a user-defined derived-type input/output procedure.
write(unit, iostat=iostat, iomsg=iomsg) this%item
--------^
test4.f90(31): error #5513: A polymorphic I/O list item requires a user-defined derived-type input/output procedure.
read(unit, iostat=iostat, iomsg=iomsg) this%item
--------^
test4.f90(47): error #5513: A polymorphic I/O list item requires a user-defined derived-type input/output procedure.
write(*,*) cont%item
----^
所以,我有两个问题:
答案 0 :(得分:2)
需要使用无限多态实体。
为容器类型添加已定义的输入/输出过程并不能解决您的问题,因为问题不在于容器本身。相反,容器的组件是多态的,需要定义的I / O过程。
不幸的是,因为该组件是无限多态的,所以无法定义这样的过程。 1
此外,实际上不会使用您定义的容器类型的I / O过程。您已为未格式化的输入和输出定义了过程,但write(*,*)
是(列表定向的)格式化输出。
至于如何解决这个问题:在某些时候你必须决定你的无限多态实体是什么。使用无限多态实体的部分原因是棘手的,因为内部和派生类型不能被视为相同。与上一个问题一样,如果您可以使用class(something_not_star)
代替class(*)
,您会发现生活更轻松。
就事情而言,select type
可能是你最大的希望。
1 定义的I / O过程可能仅适用于派生类型。
答案 1 :(得分:1)
我实现类似的方式就像这样
module container_mod
implicit none
private
!Public access vars
public :: container
type container !< Unlimited polymorphic container class
private !contents are only accessible trough the methods, no direct access is allowed
class(*), pointer :: value => null() !< value stored in container
contains
procedure :: getContent !< returns stored content (pointer)
procedure :: storeContent !< stores the provided values (sourced allocation)
procedure :: printContainer !< prints container contents (only primitive types implemented)
end type container
interface container
procedure constructor !< construct/initialize a container
end interface
程序定义如下
function getContent(this)
class(container), intent(in) :: this
class(*), pointer :: getContent
getContent => this%value
end function getContent
subroutine storeContent(this,to_store)
class(container), intent(inout) :: this
class(*), intent(in) :: to_store
allocate(this%value, source=to_store)
end subroutine storeContent
subroutine printContainer(this)
class(container), intent(in) :: this
select type(v => this%value)
type is (integer)
print *, v
type is (character(*))
print *, v(1:1)
type is (real)
print *, v
class default
print*, "[printContainer]: don't know how to print this value, ignoring"
end select
end subroutine printContainer
function constructor(to_store)
class(container), pointer :: constructor
class(*), intent(in) :: to_store
allocate(constructor)
allocate(constructor%value, source=to_store)
end function constructor
检查this repository,因为它实现了一个容器类,并在抽象的异构数组中使用它。
一旦你检索到阵列的内容很难,我就不用担心防守,这对你来说就是Fortran。如果您确实找到了方法, 请 告诉我们。