Question

我使用csv库来创建产品表。为了将其导入网站，我需要将每个特征写在一个单独的列中。

使用简单循环添加新行：

writer = csv.writer(csvfile)

for product in products:
    writer.writerow((product['price'],
                     product['vendor_code'],
                     product['characteristics']))

添加新的product：

product = []
product.append({
    'price'             : price,
    'vendor_code'       : vendor_code,
    'characteristics'   : characteristics,
})

characteristics - 包含每个特征作为单独元素的数组

如何以这种形式获取输出文件：

190$    #0172    characteristic1     characteristic2     characteristic3

characteristics - 初始化：

try:
    characteristics = []
    soup_characteristics = soup.find_all('tr', {'class' : 'product_card__product_characters_item clearfix'})
    for ch in soup_characteristics:
        characteristics.append(re.sub('\s\s+|\n',' ', ch.text))
except AttributeError:
    characteristics = ""

Answer 1

尝试解压缩特征数组：

for product in products:
    writer.writerow((product['price'],
                     product['vendor_code'],
                     *product['characteristics']))

以下是我测试的代码：

products = [{
    'price': 100,
    'vendor': 123,
    'characters': [7, 8, 9],
}]
with open('test.csv', 'w') as fo:
    writer = csv.writer(fo)
    for p in products:
        writer.writerow((
            p['price'],
            p['vendor'],
            *p['characters'],
        ))

以下是test.csv文件的内容：

100,123,7,8,9

Answer 2

您应该能够构建一个列表作为整行写入：

for product in products:
    row = [product['price'],product['vendor_code']] # [price,vendor_code]
    row.extend(product['characteristics']) # [price,vendor_code,characteristic1,characteristic2,...]
    writer.writerow(row) # writes each value in the list as a new column

数组中每个元素的新列

2 个答案: