Question

您好我是mysql编码的新手，

我正在尝试用php和mysql创建一个登录系统。只有我现在得到2个错误，我不知道如何解决它们。如果你可以帮助我，我会感激不尽。

错误讯息：警告：mysqli_num_rows（）要求参数1为mysqli_result，布尔值在第19行的/storage/ssd4/235/5867235/public_html/htmlenphp/login.inc.php中给出

警告：无法修改标头信息 - 已经发送的标头（/storage/ssd4/235/5867235/public_html/htmlenphp/login.inc.php:19上的输出）/ storage / ssd4 / 235/5866735 / public_html /htmlenphp/login.inc.php在第21行。

这是我的PHP代码：

<?php

在session_start（）;

if (isset($_POST['submit'])) {

    include 'dbh.inc.php';

    $uid = mysqli_real_escape_string($conn, $_POST['uid']);
    $pwd = mysqli_real_escape_string($conn, $_POST['pwd']);

    if (empty($uid) || empty($pwd)) {
    header("Location: index.php?login=empty");
    exit();
    } else {
        $sql = "SELECT * FROM users WHERE user_uid='$uid'";
        $result = mysqli_query($conn, $sql);
        $resultCheck = mysqli_num_rows($result);
        if ($resultCheck < 1) {
    header("Location: index.php?login=error");
    exit();   
        } else {
            if ($row = mysqli_fetch_assoc($result)) {
                $hashedPwdCheck = password_verify($pwd, $row['user_pwd']);
                if ($hashedPwdCheck == false) {
             header("Location: index.php?login=error");
             exit();               
         } elseif ($hashedPwdCheck == true) {

             $_SESSION['u_id'] = $row['user_id'];
             $_SESSION['u_first'] = $row['user_first'];
             $_SESSION['u_last'] = $row['user_last'];
             $_SESSION['u_email'] = $row['user_email'];
             $_SESSION['u_uid'] = $row['user_uid'];
             header("Location: index.php?login=succes");
             exit();  
         }
            }
        }
    }
} else {
    header("Location: index.php?login=error");
    exit();

}

PHP MYSQL错误消息尝试了一切（mysql新增）

0 个答案: