如何从路径中读取java中的文件我的路径如下：“path”：“C：\\ somefolder \\ otherfoldet \\ abc.war \\ acm.jar \\ a.properties”

Question

如何从java

中的指定路径读取文件

代码

public void readPropertyFile(String path)throws IOException {

File fp = new File(path);
        FileReader  reader = new FileReader(fp);//        java.io.FileNotFoundException: C:\json\trm\trm.jar\quartz.properties (The system cannot find the path specified)

        Properties properties = new Properties();
        properties.load(reader)
}

Exption:
java.io.FileNotFoundException: C:\json\trm\trm.jar\quartz.properties (The system cannot find the path specified)
    at java.io.FileInputStream.open0(Native Method)
    at java.io.FileInputStream.open(Unknown Source)....

Answer 1

由于您正在从WAR（acm.war）或JAR（acm.jar）内部阅读，因此需要ZipInputStream或JarInputStream。

String entryName = "a.properties";
Path path = Paths.get("C:", "somefolder", "abc.war");

try (ZipInputStream zipIn = new ZipInputStream(Files.newInputStream(path))) {
  ZipEntry entry;
  while ((entry = zipIn.getNextEntry()) != null) {
    if (entry.getName().equals(entryName) {
      // read zipIn content here to get the entry
    }
  }
}