Question

我可能误解了JSON，但为什么这段代码不起作用？

HTML

<html>
    <head>
        <title>Test</title>
        <script type="text/javascript" src="js/jquery.js"></script>
        <script type="text/javascript" src="js/main.js"></script>
    </head>
    <body>
        <div class="response">
            Name: <span class="name"></span><br>
            Password: <span class="password"></span><br>
    </body>
</html>

MAIN.JS

$(document).ready(function(){

    $.ajax({
        type: "POST",
        url: 'action.php',
        dataType: 'json',
        success: function(msg){
            $.each(msg, function(index, value){
                if (index == 'name') { $('.name').html(value.name); }
                if (index == 'password') { $('.password').html(value.password); }
            });
        },

        error: function(){
            $('.response').html("An error occurred");
        }
    });

});

action.php的

<?php

$array = array(
    0 => array(
        'name' => "Charlie",
        'password' => "none"
    ),
    1 => array(
        'name' => "Tree",
        'password' => "tree"
    )
);

echo json_encode($array);

?>

Answer 1

在您的javascript中，index将为'0'和'1'，永远不会'name'和'value'：

    success: function(msg){
        $.each(msg, function(index, value){
            $('.name').html(value.name);
            $('.password').html(value.password);
        });
    },

当然，正如现在这样，你将两次设置你的领域，只有最后一个将“坚持”

如果您只想使用'Charlie'结果，那么

    success: function(msg){
        $('.name').html(msg[0].name);
        $('.password').html(msg[0].password);
    },

和'Tree'，只需将数组下标更改为1

Answer 2

应该是

if (index == 'name') { $('.name').html(value); }
if (index == 'password') { $('.password').html(value); }

AJAX请求返回JSON，无法正常工作

2 个答案: