我有一个XML sting看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<SR Workstation="0014" Status="Active">
<OS>
<Identification Hardware="DELL" SerialNumber="123456789">Confirmed</Identification>
<CN> EXTERN</CN>
<CV>1.1.2.45</CV>
<TS>Idle</TS>
<TSS>Ok</TSS>
<ReaderStatus Reader="Icc">Enabled</ReaderStatus>
<ReaderStatus Reader="MS">Enabled</ReaderStatus>
<LPS>Unavailable</LPS>
</OS>
</SR>
我可以在VB.net中使用此脚本获取Workstation数据和状态数据
Dim sr As New System.IO.StringReader(l_Result.XMLData)
Dim doc As New Xml.XmlDocument
doc.Load(sr)
Dim reader As New Xml.XmlNodeReader(doc)
While reader.Read()
Select Case reader.NodeType
Case Xml.XmlNodeType.Element
If reader.Name = "SR" Then
If reader.GetAttribute("WorkStation") = "0014" Then
txtStatus.Text = reader.GetAttribute("Status")
txtSerial.Text = reader.GetAttribute("Identification/SerialNumber")
txtHardware.Text = reader.GetAttribute("Identification/Hardware")
lblConfirmed.Text = reader.GetAttribute("Identification")
End If
End If
End Select
End While
但是获取值123456789(SerialNumber),DELL(硬件)和确认不起作用。
有人能帮助我吗?我没有收到错误,但我的文本框和标签仍然是空的。
答案 0 :(得分:3)
Dim x = System.Xml.Linq.XElement.Parse(l_Result.XMLData), e = x...<Identification>
txtStatus.Text = x.@Status
txtSerial.Text = e.@SerialNumber
txtHardware.Text = e.@Hardware
lblConfirmed.Text = e.Value
循环元素:
For Each e In x...<ReaderStatus>
Debug.Print(e.Value)
Debug.Print(e.@Reader)
Next
答案 1 :(得分:0)
您可以使用xml linq获取后代:
Imports System.Xml
Imports System.Xml.Linq
Module Module1
Sub Main()
Dim doc As New Xml.XmlDocument
doc.Load(sr)
Dim reader As New Xml.XmlNodeReader(doc)
While Not reader.EOF
If reader.Name <> "SR" Then
reader.ReadToFollowing("SR")
End If
If Not reader.EOF Then
Dim sr As XElement = XElement.ReadFrom(reader)
If CType(sr.Attribute("WorkStation"), String) = "0014" Then
txtStatus.Text = reader.GetAttribute("Status")
txtSerial.Text = CType(sr.Descendants("SerialNumber").FirstOrDefault(), String)
txtHardware.Text = CType(sr.Descendants("Hardware").FirstOrDefault(), String)
lblConfirmed.Text = CType(sr.Descendants("Identification").FirstOrDefault(), String)
Exit While
End If
End If
End While
End Sub
End Module
答案 2 :(得分:0)
您需要使用Linq to XML。然后你的代码很简单:
Dim doc = XDocument.Parse(l_Result.XMLData)
txtStatus.Text = doc.Root.Attribute("Status").Value
txtSerial.Text = doc.Root.Element("OS").Element("Identification").Attribute("SerialNumber").Value
txtHardware.Text = doc.Root.Element("OS").Element("Identification").Attribute("Hardware").Value
lblConfirmed.Text = doc.Root.Element("OS").Element("Identification").Value