我想要实现的是简单的,在R中我可以做像
这样的事情 paste0("https\\",1:10,"whatever",11:20)
,
如何在Python中执行此操作?我发现了here,但只允许:
paste0("https\\",1:10)
。
任何人都知道如何解决这个问题,这一定很容易,但我找不到。
答案 0 :(得分:2)
@Jason ,我建议您使用以下两种方法之一来完成此任务。
✓使用列表理解和 zip()功能创建文本列表。
注意:要在屏幕上打印
\
,请使用转义序列\\
。请参阅List of escape sequences and their use。如果您认为此答案不能解决您的问题,请发表评论。我将根据您的输入和预期输出更改答案。
texts = ["https\\\\" + str(num1) + "whatever" + str(num2) for num1, num2 in zip(range(1,10),range(11, 20))]
for text in texts:
print(text)
"""
https\\1whatever11
https\\2whatever12
https\\3whatever13
https\\4whatever14
https\\5whatever15
https\\6whatever16
https\\7whatever17
https\\8whatever18
https\\9whatever19
"""
✓定义一个简单的函数 paste0(),它实现上述逻辑以返回文本列表。
import json
def paste0(string1, range1, strring2, range2):
texts = [string1 + str(num1) + string2 + str(num2) for num1, num2 in zip(range1, range2)]
return texts
texts = paste0("https\\\\", range(1, 10), "whatever", range(11, 20))
# Pretty printing the obtained list of texts using Jon module
print(json.dumps(texts, indent=4))
"""
[
"https\\\\1whatever11",
"https\\\\2whatever12",
"https\\\\3whatever13",
"https\\\\4whatever14",
"https\\\\5whatever15",
"https\\\\6whatever16",
"https\\\\7whatever17",
"https\\\\8whatever18",
"https\\\\9whatever19"
]
"""
答案 1 :(得分:1)
根据您提供的链接,这应该有效:
["https://" + str(i) + "whatever" + str(i) for i in xrange(1,11)]
提供以下输出:
['https://1whatever1', 'https://2whatever2', 'https://3whatever3',
'https://4whatever4', 'https://5whatever5', 'https://6whatever6',
'https://7whatever7', 'https://8whatever8',
'https://9whatever9', 'https://10whatever10']
修改强>
这适用于paste0("https\\",1:10,"whatever",11:20)
paste_list = []
for i in xrange(1,11):
# replace {0} with the value of i
first_half = "https://{0}".format(i)
for x in xrange(1,21):
# replace {0} with the value of x
second_half = "whatever{0}".format(x)
# Concatenate the two halves of the string and append them to paste_list[]
paste_list.append(first_half+second_half)
print paste_list