我在这里更新一个特定的contract_id
。
我需要一次更新所有contract_ids
,
即在plsql块中动态传递Contract_id。
DECLARE
VAR1 NUMBER := 0;
CURSOR C1 (P_CONTRACT_ID IN NUMBER)
IS
SELECT GO.CONTRACT_ID,
GO.COLUMN46,
GO.COLUMN1,
GO.ORG_ID
FROM XYZ GO
WHERE GO.CONTRACT_ID = P_CONTRACT_ID AND GO.COLUMN46 IS NULL;
BEGIN
BEGIN
SELECT NVL (MAX (TO_NUMBER (COLUMN46)), 0)
INTO VAR1
FROM XYZ
WHERE CONTRACT_ID = 525215;
EXCEPTION
WHEN OTHERS
THEN
VAR1 := 0;
END;
FOR F1 IN C1 (525215)
LOOP
VAR1 := VAR1 + 1;
BEGIN
UPDATE XYZ
SET COLUMN46 = VAR1
WHERE CONTRACT_ID = F1.CONTRACT_ID
AND COLUMN46 IS NULL
AND COLUMN1 = F1.COLUMN1;
EXCEPTION
WHEN OTHERS
THEN
NULL;
END;
END LOOP;
COMMIT;
EXCEPTION
WHEN OTHERS
THEN
NULL;
END;
答案 0 :(得分:0)
更改光标并删除where-condition:
CURSOR C1
IS
SELECT GO.CONTRACT_ID,
GO.COLUMN46,
GO.COLUMN1,
GO.ORG_ID
FROM XYZ GO
WHERE GO.COLUMN46 IS NULL;
你也很想在id-select中删除它:
SELECT NVL (MAX (TO_NUMBER (COLUMN46)), 0)
INTO VAR1
FROM XYZ
--WHERE CONTRACT_ID = 525215
;
您还应该阅读有关生成ID的序列和触发器的内容;-) How to create id with AUTO_INCREMENT on Oracle?