在plsql块中动态传递Contract_id

时间:2018-06-01 09:16:03

标签: oracle plsql

我在这里更新一个特定的contract_id。 我需要一次更新所有contract_ids
即在plsql块中动态传递Contract_id。

DECLARE
    VAR1   NUMBER := 0;

    CURSOR C1 (P_CONTRACT_ID IN NUMBER)
    IS
        SELECT GO.CONTRACT_ID,
               GO.COLUMN46,
               GO.COLUMN1,
               GO.ORG_ID
          FROM XYZ GO
         WHERE GO.CONTRACT_ID = P_CONTRACT_ID AND GO.COLUMN46 IS NULL;
BEGIN
    BEGIN
        SELECT NVL (MAX (TO_NUMBER (COLUMN46)), 0)
          INTO VAR1
          FROM XYZ
         WHERE CONTRACT_ID = 525215;
    EXCEPTION
        WHEN OTHERS
        THEN
            VAR1 := 0;
    END;

    FOR F1 IN C1 (525215)
    LOOP
        VAR1 := VAR1 + 1;

        BEGIN
            UPDATE XYZ
               SET COLUMN46 = VAR1
             WHERE     CONTRACT_ID = F1.CONTRACT_ID
                   AND COLUMN46 IS NULL
                   AND COLUMN1 = F1.COLUMN1;
        EXCEPTION
            WHEN OTHERS
            THEN
                NULL;
        END;
    END LOOP;

    COMMIT;
EXCEPTION
    WHEN OTHERS
    THEN
        NULL;
END;

1 个答案:

答案 0 :(得分:0)

更改光标并删除where-condition:

CURSOR C1
IS
    SELECT GO.CONTRACT_ID,
           GO.COLUMN46,
           GO.COLUMN1,
           GO.ORG_ID
      FROM XYZ GO
     WHERE GO.COLUMN46 IS NULL;

你也很想在id-select中删除它:

    SELECT NVL (MAX (TO_NUMBER (COLUMN46)), 0)
      INTO VAR1
      FROM XYZ
     --WHERE CONTRACT_ID = 525215
     ;

您还应该阅读有关生成ID的序列和触发器的内容;-) How to create id with AUTO_INCREMENT on Oracle?