Question

我正在尝试编写一个简单的c程序，但我无法声明“字符串”数组。以下代码编译时没有错误：

#define HAND_SIZE 10;
int main()
{
    char * cards[13] = { "A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};

    int player[HAND_SIZE];
}

但是我不能让玩家变成一串“字符串”而不是整数。如果我执行以下任何操作：

char * player[HAND_SIZE];

char player [HAND_SIZE][];

char player [HAND_SIZE][5];

//repeat the above with '= {}' and '= {""}' initializations

我收到错误：

 error: expected ‘]’ before ‘;’ token

为什么会发生这种情况？如何在c？

中声明一个空数组“字符串”

Answer 1

预处理程序指令不应以分号结尾。

#define行结束后的分号给出了错误，这将有效：

#define HAND_SIZE 10
int main()
{
    char * cards[13] = { "A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};

    int player[HAND_SIZE];
}

gcc数组的“字符串”声明失败

1 个答案: