Question

我想重现从新图的数字到子图的情节。请考虑以下

f1 = figure;
p1 = plot([1 2],[1 2], 'r');
legend(p1, 'Test')

f2 = figure;
p2 = plot([2 3], [2 3], 'g');

f3 = figure;

h1 = subplot(1,2,1);
h2 = subplot(1,2,2);

现在，我的目的是将p1和p2复制为f3的子图。我尝试过许多组合，包括以下内容，但没有效果

ax1 = copyobj(f1.Children, h1);
ax2 = copyobj(f2.Children, h2);

this link对类似问题的回答没有帮助。我正在使用R2016b。

Answer 1

这对我有用：

#Imports
import time
import random

#If more than 7 letters and numbers
def CheckPlate(np):
    IsPlateValid = False
    if len(np) != 7:
        print("Invalid Plate Number!")
    else:
        IsPlateValid = True
    return IsPlateValid

#If less than 7 letters and numbers outputs number plate and speed

def CheckPlateContent(twoletters, twonumbers, threeletters):
    twoletterstf=False
    twonumberstf=False
    threeletterstf=False
    valid = False
    for letter in twoletters: #I have to use (for x in Xs) because of array input but your format should work fine here  if input is user input
        if letter.isupper() and letter.isalpha():
            twoletterstf = True
    for number in twonumbers:
        if number.isdigit():
            twonumberstf = True
    for letter in threeletters:
        if letter.isupper() and letter.isalpha():
            threeletterstf = True
    if (twoletterstf == True and twonumberstf == True and threeletterstf == True):
        valid= True
    else:
        print("Invalid Plate Number!")
    return valid

def SpeedCheck(speed):
    ticket = False
    ticketprice = 0
    if speed >= 31:
        ticket=True
        ticketprice=100+speed
    return ticket, ticketprice

def main():
    #Gets the number plate
    np=['A','C','4','2','F','G','H'] #input is an array because I id this on Atom and there is no input console.

    #Sets the parts of the license plate
    twoletters=np[0:2]
    twonumbers=np[2:4]
    threeletters=np[4:7]

    #Sensors
    sensor1=0
    sensor2=random.uniform(0.25, 0.4)
    sensor2=round(sensor2, 1)

    #Variables
    speed=0
    ticketprice=0
    ticket=False
    distance=10

    #Calculations to work out the speed
    time.sleep(1)
    distance=10
    times=sensor2-sensor1
    ans=1/times
    speed=distance*ans

    bool = CheckPlate(np)
    valid = CheckPlateContent(twoletters, twonumbers, threeletters)
    ticket, ticketprice = SpeedCheck(speed)

    print ("Number Plate:" + str(np) + "\n")
    print ("Valid:" + str(valid) + "\n")
    print ("Speed:" + str(speed) + "M/S" + "\n")
    print ("Ticket:" + str(ticket) + "\n")
    print ("Ticket Price: £" + str(ticketprice) + "\n")


if __name__ == "__main__":
    main()

图3显示了两个子图，其中包含p1和p2中的数据：

Matlab：绘制子图

1 个答案: