我需要获得一个月的周列表,周一作为开始日。
例如,对于2009年2月,此方法将返回:
2/2/2009
2/9/2009
2/16/2009
2/23/2009
答案 0 :(得分:25)
// Get the weeks in a month
DateTime date = DateTime.Today;
// first generate all dates in the month of 'date'
var dates = Enumerable.Range(1, DateTime.DaysInMonth(date.Year, date.Month)).Select(n => new DateTime(date.Year, date.Month, n));
// then filter the only the start of weeks
var weekends = from d in dates
where d.DayOfWeek == DayOfWeek.Monday
select d;
答案 1 :(得分:10)
public static List<DateTime> GetWeeks(
this DateTime month, DayOfWeek startOfWeek)
{
var firstOfMonth = new DateTime(month.Year, month.Month, 1);
var daysToAdd = ((Int32)startOfWeek - (Int32)month.DayOfWeek) % 7;
var firstStartOfWeek = firstOfMonth.AddDays(daysToAdd);
var current = firstStartOfWeek;
var weeks = new List<DateTime>();
while (current.Month == month.Month)
{
weeks.Add(current);
current = current.AddDays(7);
}
return weeks;
}
答案 2 :(得分:3)
以下是使用C#3.0 / LINQ的解决方案(实际上是一行),如果您有兴趣:
var month = new DateTime(2009, 2, 1);
var weeks = Enumerable.Range(0, 4).Select(n => month.AddDays(n * 7 - (int)month.DayOfWeek + 1)).TakeWhile(monday => monday.Month == month.Month);
答案 3 :(得分:1)
int year = 2009;
int month = 2;
DateTime startDate = new DateTime(year, month, 1);
DateTime endDate = startDate.AddMonths(1);
while (startDate.DayOfWeek != DayOfWeek.Monday)
startDate = startDate.AddDays(1);
for (DateTime result = startDate; result < endDate; result = result.AddDays(7))
DoWhatYouWant(result);
答案 4 :(得分:1)
这个怎么样?
public IEnumerable<DateTime> GetWeeks(DateTime date, DayOfWeek startDay)
{
var list = new List<DateTime>();
DateTime first = new DateTime(date.Year, date.Month, 1);
for (var i = first; i < first.AddMonths(1); i = i.AddDays(1))
{
if (i.DayOfWeek == startDay)
list.Add(i);
}
return list;
}
答案 5 :(得分:0)
只需将响应行更改为您需要执行的操作
protected void PrintDay(int year, int month, DayOfWeek dayName)
{
CultureInfo ci = new CultureInfo("en-US");
for (int i = 1 ; i <= ci.Calendar.GetDaysInMonth (year, month); i++)
{
if (new DateTime (year, month, i).DayOfWeek == dayName)
Response.Write (i.ToString() + "<br/>");
}
}
快速解决方案:我认为它没有内置功能....
答案 6 :(得分:0)
以下伪代码应该可以工作:
答案 7 :(得分:0)
我看到你得到了答案,但我想与你分享我为我的一个项目创建的帮助班。这是一个综合性的课程,但可能有所帮助......
public static class WeekHelper {
#region Public Methods
public static DateTime GetWeekStart(DateTime date) {
DateTime weekStart;
int monday = 1;
int crtDay = (int)date.DayOfWeek;
if (date.DayOfWeek == DayOfWeek.Sunday)
crtDay = 7;
int difference = crtDay - monday;
weekStart = date.AddDays(-difference);
return weekStart;
}
public static DateTime GetWeekStop(DateTime date) {
DateTime weekStart;
int sunday = 7;
int crtDay = (int)date.DayOfWeek;
if (date.DayOfWeek == DayOfWeek.Sunday)
crtDay = 7;
int difference = sunday - crtDay;
weekStart = date.AddDays(difference);
return weekStart;
}
public static void GetWeekInterval(int year, int weekNo,
out DateTime weekStart, out DateTime weekStop) {
GetFirstWeekOfYear(year, out weekStart, out weekStop);
if (weekNo == 1)
return;
weekNo--;
int daysToAdd = weekNo * 7;
DateTime dt = weekStart.AddDays(daysToAdd);
GetWeekInterval(dt, out weekStart, out weekStop);
}
public static List<KeyValuePair<DateTime, DateTime>> GetWeekSeries(DateTime toDate) {
//gets week series from beginning of the year
DateTime dtStartYear = new DateTime(toDate.Year, 1, 1);
List<KeyValuePair<DateTime, DateTime>> list = GetWeekSeries(dtStartYear, toDate);
if (list.Count > 0) {
KeyValuePair<DateTime, DateTime> week = list[0];
list[0] = new KeyValuePair<DateTime, DateTime>(dtStartYear, week.Value);
}
return list;
}
public static List<KeyValuePair<DateTime, DateTime>> GetWeekSeries(DateTime fromDate, DateTime toDate) {
if (fromDate > toDate)
return null;
List<KeyValuePair<DateTime, DateTime>> list = new List<KeyValuePair<DateTime, DateTime>>(100);
DateTime weekStart, weekStop;
toDate = GetWeekStop(toDate);
while (fromDate <= toDate) {
GetWeekInterval(fromDate, out weekStart, out weekStop);
list.Add(new KeyValuePair<DateTime, DateTime>(weekStart, weekStop));
fromDate = fromDate.AddDays(7);
}
return list;
}
public static void GetFirstWeekOfYear(int year, out DateTime weekStart, out DateTime weekStop) {
DateTime date = new DateTime(year, 1, 1);
GetWeekInterval(date, out weekStart, out weekStop);
}
public static void GetWeekInterval(DateTime date,
out DateTime dtWeekStart, out DateTime dtWeekStop) {
dtWeekStart = GetWeekStart(date);
dtWeekStop = GetWeekStop(date);
}
#endregion Public Methods
}
答案 8 :(得分:0)
这很好用!所有你需要做的就是获得你想要获得周数的月份的第一天,然后这将给你每周的第一天。您需要获得5周(而不是4周),因此Enumerable.Range计算出5而不是4。
var date = new DateTime(DateTime.Today.Year, DateTime.Today.Month, 1);
var weeks = from n in Enumerable.Range(0, 5)
select date.AddDays(7 * n + (-1 * (int)date.DayOfWeek));
答案 9 :(得分:0)
这就是我所做的,使用Chaowlert的代码作为起始基础。基本上我修改了你需要检查是否将溢出的天数添加到下个月,所以我不会添加4天(星期一到星期五),但实际上是4天和剩余天数之间的最小值。这个月。另外,我检查当天是否是周末,否则直到工作日为止。我的目的是打印一个月内的星期几,从星期一到星期五
DateTime fechaInicio = new DateTime(año, mes, 1);
DateTime fechaFin = fechaInicio.AddMonths(1);
int diasHastaFinMes = 0;
while (esFinDeSemana(fechaInicio))
fechaInicio = fechaInicio.AddDays(1);
for (DateTime fecha = fechaInicio; fecha < fechaFin; fecha = fecha.AddDays(7))
{
diasHastaFinMes = DateTime.DaysInMonth(fecha.Year, fecha.Month) - fecha.Day;
printWeeks(fecha, fecha.AddDays(Math.Min(4, diasHastaFinMes)));
}