在Polly重试策略中重用HttpRequestMessage

时间:2018-05-24 20:00:08

标签: c# dotnet-httpclient polly

HttpRequestMessage对象只能使用一次;将来尝试使用同一个对象会抛出异常。我正在使用Polly重试一些请求,我正在解决这个问题。我知道如何克隆请求,SO上有很多例子,但我无法弄清楚如何克隆请求并在Polly重试时发送新请求。我怎么能做到这一点?

这些是我的政策,仅供参考。这是一个Xamarin应用程序。我想在网络出现故障时重试几次,如果响应未经授权,我想用保存的凭据重新验证并再次尝试原始请求。

public static PolicyWrap<HttpResponseMessage> RetryPolicy
{
    get => WaitAndRetryPolicy.WrapAsync(ReAuthPolicy);
}

private static IAsyncPolicy WaitAndRetryPolicy
{
    get => Policy.Handle<WebException>().WaitAndRetryAsync(4, _ => TimeSpan.FromSeconds(2));
}

private static IAsyncPolicy<HttpResponseMessage> ReAuthPolicy
{
    get => Policy.HandleResult<HttpResponseMessage>(x => x.StatusCode == HttpStatusCode.Unauthorized)
        .RetryAsync((_, __) => CoreService.LogInWithSavedCredsAsync(true));
}

由于HttpRequestMessage重用,这不起作用,但这正是我想要实现的目标:

var request = new HttpRequestMessage(HttpMethod.Post, "some_endpoint")
{
    Content = new StringContent("some content")
};

request.Content.Headers.ContentType = new MediaTypeHeaderValue("application/json");

var policyResponse = await ConnectivityHelper.RetryPolicy
    .ExecuteAndCaptureAsync(() => _client.SendAsync(request)).ConfigureAwait(false);

// handle outcome

1 个答案:

答案 0 :(得分:0)

如果重复使用 InvalidOperationException,则抛出 HttpRequestMessage 的代码是 HttpClient 本身内的验证步骤。

    private static void CheckRequestMessage(HttpRequestMessage request)
    {
        if (!request.MarkAsSent())
        {
            throw new InvalidOperationException(SR.net_http_client_request_already_sent);
        }
    }

https://github.com/microsoft/referencesource/blob/e7b9db69533dca155a33f96523875e9c50445f44/System/net/System/Net/Http/HttpClient.cs#L628-L634

    internal bool MarkAsSent()
    {
        return Interlocked.Exchange(ref sendStatus, messageAlreadySent) == messageNotYetSent;
    }

https://github.com/microsoft/referencesource/blob/5697c29004a34d80acdaf5742d7e699022c64ecd/System/net/System/Net/Http/HttpRequestMessage.cs#L193

您可以将 polly 重试策略放在 DelegatingHandler 中,这样就可以了。它还提供了一个很好的 SoC(关注点分离)。如果以后您不想重试或更改重试行为,只需删除 DelegatingHandler 或更改它。注意处理 HttpRequestMessage 和中间 HttpResponseMessage 对象。