Question

我必须找到一组带有共享密钥的结果，该共享密钥已在过去90天内发布到我的本地数据存储的API，但不会晚于过去7天。

这将是我需要捕获1234的有效组：

account_id,company_id,posted_date
1234,A,2018-02-28
1234,B,2018-03-13
1234,C.2018-04-23
1234,D,2018-05-15

这将是一个无效的组。如果单个日期超出查询的上限或下限，则应从最终结果中排除帐户ID：

account_id,company_id,posted_date
5678,Z,2018-02-01
5678,Y,2018-03-13
5678,X.2018-04-23
5678,W,2018-05-21

这是使用子查询的查询的第一个草稿：

SELECT DISTINCT account_id, company_id FROM local_data_store.result_api
WHERE account_id NOT IN (
    SELECT account_id FROM local_data_store.result_api
    GROUP BY account_id
    HAVING posted_date > DATE_SUB(NOW(), INTERVAL 7 DAY)
)
AND account_did IN (
    SELECT account_did FROM local_data_store.result_api
    GROUP BY account_did
    HAVING posted_date > DATE_SUB(NOW(), INTERVAL 90 DAY)
)
GROUP BY account_id, company_id
LIMIT 100000;

这是我现在正在处理的没有子查询的查询（我尝试过加入，但他们确实没有工作）：

SELECT DISTINCT account_id, company_id, 
COUNT(ra1.posted_date > DATE_SUB(NOW(), INTERVAL 90 DAY)) AS day90, 
COUNT(ra1.posted_date > DATE_SUB(NOW(), INTERVAL 7 DAY)) as day7
FROM local_data_store.result_api ra1
GROUP BY posted_date, account_id;

但它运行的时间太长，以至于数据库连接超时。这仅适用于375,000行的数据库表。

Answer 1

这是我想出的解决方案。希望对别人有帮助。

SELECT DISTINCT account_did, cb_company_id, COUNT(did) as `# of jobs`
FROM cb_local_data_store.job_search_result_api 
WHERE account_did NOT IN (
SELECT account_did FROM cb_local_data_store.job_search_result_api
WHERE posted_date < DATE_SUB(NOW(), INTERVAL 60 DAY)
OR posted_date > DATE_SUB(NOW(), INTERVAL 4 DAY) )
GROUP BY account_did, cb_company_id

如何在MySQL中两个日期之间专门找到一组行？

1 个答案: