Question

我正在尝试从mySQL数据库中获取记录并对它们进行分组。让我们以此表为例：

+++++++++++++++++++++++++++++++++++++++++++++++++++++
DATEADDED            DOCTYPE     SUBJECT    DETAILS
2018-03-03 9:54:54   DOCUMENT     Letter     Outgoing
2018-03-03 8:54:54   PARCEL       Mail       Incoming
2018-03-04 8:55:54   PARCEL       Mail       Incoming
2018-03-04 8:55:54   DOCUMENT     Mail       Outgoing
+++++++++++++++++++++++++++++++++++++++++++++++++++++

我想要做的是按日期（没有时间）对这些数据进行分组，然后按TYPE和COUNT进行分组，使它看起来像这样：

+++++++++++++++++++
DATE: April 3, 2018
      DOCUMENT - 1
      PARCEL -   1
 TOTAL-----------2

DATE: April 4, 2018
      DOCUMENT - 1
      PARCEL -   1
 TOTAL-----------2                     
++++++++++++++++++++

尝试使用以下代码：

<?php 
foreach($page->query('SELECT id,dateAdded,COUNT(*) FROM seclogs GROUP BY DATE(dateAdded) desc') as $row) { ?><tr>
<td><?php echo date("Y-m-d", strtotime($row['dateAdded'])); ?></td>
<td><?php 

$thisDate=date(strtotime($row['dateAdded']));
foreach($page->query("SELECT id,dateAdded,docType,COUNT(*) FROM seclogs WHERE DATE(dateAdded) LIKE '$thisDate' GROUP BY docType desc") as $row2) {

echo $row2['docType']."-".$row2['COUNT(*)']."<br/>"; } ?><br/><b><?php echo "Total: ".$row['COUNT(*)'].""; ?></b> </td> 
</tr><?php } ?>

但它只显示以下输出：

+++++++++++++++++++
DATE: April 3, 2018


 TOTAL-----------2

DATE: April 4, 2018


 TOTAL-----------2                     
++++++++++++++++++++

我一直在各地工作和搜索这个问题，但无法找到答案。任何帮助将不胜感激。

Answer 1

您想要的确切输出实际上是一个演示文稿，可以很容易地在您的PHP代码中处理。至于查询，我将使用以下原始数据：

SELECT
    DATE(dateAdded) AS dateAdded,
    docType,
    COUNT(*) AS cnt
FROM seclogs
GROUP BY
    DATE(dateAdded),
    docType
ORDER BY
    DATE(dateAdded),
    docType;

当然，这不会给你想要的输出，至少不完全。你现在需要做的是使用一个循环，它只在每个日期/类型组的开头打印日期。

使用PHP PDO进行双重分组

1 个答案: