Question

我有一个任务输入一个奇数位数字并打印成沙漏形状。例如，如果输入数字为3，则打印应该如下所示。

int[] lastNum = arr[arr.length - 1];
System.out.println(lastNum[0]);

我成功打印出这样的内容：

但在那之后我卡住了。这是我的代码

12321
12321

Answer 1

这是你想要的吗？

#include <stdio.h>

unsigned int digits(unsigned int number)
{
    unsigned int digits_counter = 0;
    while (number)
    {
        number /= 10;
        ++digits_counter;
    }
    return digits_counter;
}

void printNumber(unsigned int minLevel, unsigned int number)
{
  if(number > minLevel)
  {
    printf("%d");
  }
  else
  {
    printf("%*c", digits(number), ' ');
  }
}

void hourglass_line(unsigned int minLevel, unsigned int level)
{
  int number;
  /// rising
  for(number = 1; number <= level; ++number)
  {
    printNumber(minLevel, number);
  }
  // falling
  for(number = level; number >= 1; --number)
  {
    printNumber(minLevel, number);
  }
  printf("\n");
}

void hourglass(unsigned int level)
{
  int minLevel;
  /// upper side and center
  for (minLevel = 0; minLevel < level; ++minLevel)
  {
    hourglass_line(minLevel, level);
  }
  // lower side
  for (minLevel = level-2; minLevel >= 0; --minLevel)
  {
    hourglass_line(minLevel, level);
  }
}

int main()
{
  unsigned int number;
  printf("give me a number: \n");
  scanf("%d", &number);
  hourglass(number);
  return 0;
}

c：输入一位数字，打印沙漏形状

1 个答案: