Question

我想声明x对于二进制0,1

是可变的

i和k表示流矩阵中的设施，j和q表示距离矩阵中的位置。

x（i，j）表示如果i（设施）在j（位置）中分配，则x将等于1.

如果将设施i分配给位置j，则

x（i，j）= 1，否则，xij = 0，所以否则意味着如果x（k，q）= 1，则x（i，J）将为0 ......

手动计算的例子

Min =（f i1，k1 * d j1，q1 * x i1，j1 * x k1，q1）+（f i1，k1 * d j1，q2 * x i1，j1 * x k1，q2）+（ f i1，k1 * d j1，q3 * x i1，j1 * x k1，q3）....

（0 * 0 * 1 * 1）+（0 * 6 * 1 * 0）+（0 * 8 * 1 * 0）.....

我想* xi1，j1 * xk1，q1为0或1 ..如果我选择i1，j1 = 1则另一个将为0 ..例如i2，j1将等于0

下面是编码

clc;
clear;
%sum sum sum sum(fik*djq*xij*xkq)
%i,k= facilities
%j,q= location
%f(i,k)= flow between facilities i and k
%d(j,q)= distance between locations j and q
%xij = 1 if facility i is assigned to location j and if otherwise, xij = 0
% Flow matrix: flow assigning facility i (column) to facility k (row)
f = [0 5 7 9;
     5 0 4 6;
     7 4 0 3;
     9 6 3 0];
%Distance matrix: distance assigning location j (column) to location q (row)
d = [0 6 8 9;
     6 0 5 1;
     8 5 0 2;
     9 1 2 0];
 z= 0;
 nf= 4;
 nd= 4;
 for i=1:nf 
     for j=1:nf 
         for k=1:nd 
             for q=1:nd 
                 z = min('z','f(i,k)*d(j,q)*x(i,j)*x(k,q)'); 
             end
         end
     end
 end
%Constraints
%The first set of constraints requires that each facility gets exactly one 
%location, that is for each facility, the sum of the location values 
%corresponding to that facility is exactly one
 Constraints.constr1 = sum(x,2) == 1;
%The second set of constraints are inequalities. These constraints specify 
%that each office has no more than one facility in it.
 Constraints.constr2 = sum(x,1) == 1;
 disp (z);

Answer 1

使用直肠

此reperm用于精炼编码中的0,1

我如何创建二进制[0,1]？

1 个答案: