我有两个数组。第一个是通过创建数组$properties
的块来创建的。
$array1 = array_chunk($properties,10000,true);
看起来像这样:
array(4) {
[0]=>
array(10000) {
["12345"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 19:46:25"
["fileName"]=>
string(46) "monkey.jpg"
["path"]=>
string(149) "Volumes/animals/monkey.jpg"
["size"]=>
string(7) "2650752"
}
["678790"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 14:39:43"
["fileName"]=>
string(45) "elephant.jpg"
["path"]=>
string(171) "Volumes/animals/elephant.jpg"
["size"]=>
string(7) "2306688"
}
... and so on.
另一个是从数据库创建的:
$countResult = "SELECT COUNT(*) AS `count` FROM files";
$q = $pdo->prepare($countResult);
$q->execute();
$row = $q->fetch(PDO::FETCH_ASSOC);
$totalCount = $row['count'];
$chunkSize = 10000;
$from = 0;
while($from < $totalCount)
{
$sql = 'SELECT id, dateTime, fileName, path, size FROM files LIMIT ' . $from . ', ' . $chunkSize . ';';
$q = $pdo->prepare($sql);
$q->execute();
$rows = $q->fetchAll(PDO::FETCH_GROUP | PDO::FETCH_UNIQUE | PDO::FETCH_ASSOC);
echo "<pre>";
var_dump($rows);
echo "</pre>";
$from += $chunkSize;
}
var_dump($rows)
的结果是:
array(10000) {
["12345"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 19:46:25"
["fileName"]=>
string(46) "monkey.jpg"
["path"]=>
string(149) "Volumes/animals/monkey.jpg"
["size"]=>
string(7) "2650752"
}
["678790"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 14:39:43"
["fileName"]=>
string(45) "elephant.jpg"
["path"]=>
string(171) "Volumes/animals/elephant.jpg"
["size"]=>
string(7) "2306688"
}
and so on...
array(10000) {
["23424"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 14:46:25"
["fileName"]=>
string(46) "rabbit.jpg"
["path"]=>
string(149) "Volumes/animals/rabbit.jpg"
["size"]=>
string(7) "2655752"
}
["163452"]=>
array(5) {
["dateTime"]=>
string(19) "2016-10-12 12:39:43"
["fileName"]=>
string(45) "snake.jpg"
["path"]=>
string(171) "Volumes/animals/snake.jpg"
["size"]=>
string(7) "2406688"
}
and so on...
所以$array1
是一个分裂的数组,看起来好像它仍然是一个包含4个数组的数组......(我真的不明白这一点),但是:我需要创建一个来自mysql数据库输入的数组($array2
)看起来与$array1
完全一样,我不知道如何实现。我的目的是要比较$array1
和$array2
支票是否匹配。
答案 0 :(得分:1)
在while之前创建数组,然后从数据库中推送数据:
//create the array here
$rows = [];
while($from < $totalCount)
{
$sql = 'SELECT id, dateTime, fileName, path, size FROM files LIMIT ' . $from . ', ' . $chunkSize . ';';
$q = $pdo->prepare($sql);
$q->execute();
//HERE $rows[]
$rows[] = $q->fetchAll(PDO::FETCH_GROUP | PDO::FETCH_UNIQUE | PDO::FETCH_ASSOC);
echo "<pre>";
var_dump($rows);
echo "</pre>";
$from += $chunkSize;
}
然后比较您想要的方式,数组$rows
与$array1