如何从数组的foreach循环创建数组?

时间:2018-05-16 17:28:59

标签: php mysql arrays foreach chunks

我有两个数组。第一个是通过创建数组$properties的块来创建的。

$array1 = array_chunk($properties,10000,true);

看起来像这样:

array(4) {
  [0]=>
  array(10000) {
    ["12345"]=>
    array(5) {
      ["dateTime"]=>
      string(19) "2016-10-12 19:46:25"
      ["fileName"]=>
      string(46) "monkey.jpg"
      ["path"]=>
      string(149) "Volumes/animals/monkey.jpg"
      ["size"]=>
      string(7) "2650752"
    }
    ["678790"]=>
    array(5) {
      ["dateTime"]=>
      string(19) "2016-10-12 14:39:43"
      ["fileName"]=>
      string(45) "elephant.jpg"
      ["path"]=>
      string(171) "Volumes/animals/elephant.jpg"
      ["size"]=>
      string(7) "2306688"
    }

... and so on.

另一个是从数据库创建的:

  $countResult = "SELECT COUNT(*) AS `count` FROM files"; 
  $q = $pdo->prepare($countResult);
  $q->execute();
  $row = $q->fetch(PDO::FETCH_ASSOC);
  $totalCount = $row['count'];
  $chunkSize = 10000;
  $from      = 0;

while($from < $totalCount)
{
   $sql = 'SELECT id, dateTime, fileName, path, size FROM files LIMIT ' . $from . ', ' . $chunkSize . ';'; 
   $q = $pdo->prepare($sql);
   $q->execute();
   $rows = $q->fetchAll(PDO::FETCH_GROUP | PDO::FETCH_UNIQUE | PDO::FETCH_ASSOC);

   echo "<pre>";
   var_dump($rows);
   echo "</pre>";

   $from += $chunkSize;
}

var_dump($rows)的结果是:

array(10000) {
  ["12345"]=>
  array(5) {
         ["dateTime"]=>
          string(19) "2016-10-12 19:46:25"
          ["fileName"]=>
          string(46) "monkey.jpg"
          ["path"]=>
          string(149) "Volumes/animals/monkey.jpg"
          ["size"]=>
          string(7) "2650752"
  }
  ["678790"]=>
  array(5) {
      ["dateTime"]=>
          string(19) "2016-10-12 14:39:43"
          ["fileName"]=>
          string(45) "elephant.jpg"
          ["path"]=>
          string(171) "Volumes/animals/elephant.jpg"
          ["size"]=>
          string(7) "2306688"
  }

and so on...

array(10000) {
  ["23424"]=>
  array(5) {
         ["dateTime"]=>
          string(19) "2016-10-12 14:46:25"
          ["fileName"]=>
          string(46) "rabbit.jpg"
          ["path"]=>
          string(149) "Volumes/animals/rabbit.jpg"
          ["size"]=>
          string(7) "2655752"
  }
  ["163452"]=>
  array(5) {
      ["dateTime"]=>
          string(19) "2016-10-12 12:39:43"
          ["fileName"]=>
          string(45) "snake.jpg"
          ["path"]=>
          string(171) "Volumes/animals/snake.jpg"
          ["size"]=>
          string(7) "2406688"
  }


and so on...

所以$array1是一个分裂的数组,看起来好像它仍然是一个包含4个数组的数组......(我真的不明白这一点),但是:我需要创建一个来自mysql数据库输入的数组($array2)看起来与$array1完全一样,我不知道如何实现。我的目的是要比较$array1$array2支票是否匹配。

1 个答案:

答案 0 :(得分:1)

在while之前创建数组,然后从数据库中推送数据:

//create the array here
$rows = [];
while($from < $totalCount)
{
   $sql = 'SELECT id, dateTime, fileName, path, size FROM files LIMIT ' . $from . ', ' . $chunkSize . ';'; 
   $q = $pdo->prepare($sql);
   $q->execute();
   //HERE $rows[]
   $rows[] = $q->fetchAll(PDO::FETCH_GROUP | PDO::FETCH_UNIQUE | PDO::FETCH_ASSOC);

   echo "<pre>";
   var_dump($rows);
   echo "</pre>";

   $from += $chunkSize;
}

然后比较您想要的方式,数组$rows$array1