在DirectX

时间:2018-05-16 08:01:22

标签: c++ windows multithreading directx directx-11

我在具有两个线程的DirectX应用程序中遇到数据竞争:消费者和生产者。

第一个线程( producer )是一个屏幕抓取器,它使用desktop duplication来获取纹理中的桌面图像。它在适配器X上创建了ID3D11Device和ID3D11DeviceContext。

dxgi_dd->AcquireNextFrame(INFINITE, &frame_info, &desktop_resource);

ID3D11Texture2D *desktop_texture;
desktop_resource->QueryInterface(__uuidof(ID3D11Texture2D), (void **)&desktop_texture);
desktop_resource->Release();

D3D11_TEXTURE2D_DESC texture_desc;

memset(&texture_desc, 0, sizeof(texture_desc));
texture_desc.Width = desktop_desc.Width;
texture_desc.Height = desktop_desc.Height;
texture_desc.MipLevels = 1;
texture_desc.ArraySize = 1;
texture_desc.Format = DXGI_FORMAT_B8G8R8A8_UNORM;
texture_desc.SampleDesc.Count = 1;
texture_desc.SampleDesc.Quality = 0;
texture_desc.Usage = D3D11_USAGE_DEFAULT;
texture_desc.BindFlags = 0;
texture_desc.CPUAccessFlags = 0;
texture_desc.MiscFlags = 0;

d3d11_device->CreateTexture2D(&texture_desc, NULL, &return_texture);

// Copy it to a return texture
immediate_context->CopyResource(return_texture, desktop_texture);
immediate_context->Flush();

dxgi_dd->ReleaseFrame();
desktop_texture->Release();

return encapsulate(return_texture); // Thread returns the pointer encapsulated in a structure

第二个线程(消费者)在相同的适配器X

上的ID3D11Device和ID3D11DeviceContext
ID3D11Texture2D *dx_input_texture;
D3D11_TEXTURE2D_DESC desc;
ZeroMemory(&desc, sizeof(D3D11_TEXTURE2D_DESC));
desc.Width = received_texture.width;
desc.Height = received_texture.height;
desc.MipLevels = 1;
desc.ArraySize = 1;
desc.Format = DXGI_FORMAT_B8G8R8A8_UNORM;
desc.SampleDesc.Count = 1;
desc.Usage = D3D11_USAGE_DEFAULT;
desc.BindFlags = D3D11_BIND_RENDER_TARGET;
desc.CPUAccessFlags = 0;
d3d11_device->CreateTexture2D(&desc, NULL, &dx_input_texture)

ID3D11Texture2D *frame_texture = (ID3D11Texture2D*)received_texture.pointer_received_from_other_thread;

immediate_context->CopyResource(dx_input_texture, frame_texture);
immediate_context->Flush();

// Use dx_input_texture now

不幸的是,我遇到了这种方法的随机问题(无效的纹理或指针导致其他DX库期望有效的纹理失败),如果我在生产者线程中放置sleep(1000),它就会消失。这让我觉得它可能是数据竞争的事情。

两个线程是否需要同步?我现在故意跳过纹理Release()(即使我最终可能用完了GPU内存)来调试这个数据竞争。

1 个答案:

答案 0 :(得分:0)

  • 您的代码发布指针desktop_texture->Release();然后由于某种原因返回它,这看起来像一个错字,它可能应该是return encapsulate(return_texture);
  • 要使用不同的设备处理纹理,您需要使用D3D11_RESOURCE_MISC_SHARED标记创建资源,通过调用HANDLE将其转换为IDXGIResource::GetSharedHandle,然后通过致电ID3D11Device::OpenSharedResource