Question

我是使用Nightwatch的新手，我需要以下方面的帮助：

我需要检查表上名称列上的哪个单元格等于文本，例如name3

这是我的以下脚本，但它不起作用

＆＃13;

var name3 = client.globals.item3.name
for (i = 1; i <=10; i++){
            client.getText("#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child("+ i +") > div > div:nth-child(4) > div > div > a > span", function(result) {
            
    client.expect.element("#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child("+ i +") > div > div:nth-child(4) > div > div > a > span").text.to.equal(name3);
                
    client.verify.elementPresent('#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child('+ i +') > div > div:nth-child(4) > div > div > a')
                
    client.verify.containsText('#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child('+ i +') > div > div:nth-child(4) > div > div > a', name3)
  i = 11;
  });

}

＆＃13;

Answer 1

这完全是因为nodejs的异步行为。试试这个

function test(i) {
var name3 = client.globals.item3.name    
      client.getText("#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child(" + i + ") > div > div:nth-child(4) > div > div > a > span", function(result) {

                  client.expect.element("#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child(" + i + ") > div > div:nth-child(4) > div > div > a > span").text.to.equal(name3);

                  client.verify.elementPresent('#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child(' + i + ') > div > div:nth-child(4) > div > div > a')

                  client.verify.containsText('#table > div.ReactTable.noBorder-undefined.noHeader-undefined.compact-undefined.expanded-undefined.no-data-false.subComponentLarge-undefined.undefined.editable-table > div.rt-table > div.rt-tbody > div:nth-child(' + i + ') > div > div:nth-child(4) > div > div > a', name3)
              }

              while (j <= 10) {
                  test(j);
                  j++;
              }

让我知道它是否有效

检查名称列上的哪个单元格等于某个文本

1 个答案: