这就是CSV列中的单元格如何
[u"ABC||||'ABCDadfasf||||'random something', 'another random']
[u"ABCD||||'ABCDadfasf||||'random somethingadf', 'another random adsd']
[u"ABDC||||'ABCDasdadfasf||||'random something random', 'another something random']
`
我想像下面这样打破它。根据(' ||||')
拆分Col 1 Col 2 Col 3
[u"ABC ABCDadfasf 'random something', 'another random']
[u"ABCD ABCDadfasf 'random somethingadf', 'another random adsd']
[u"ABDC ABCDasdadfasf 'random something random', 'another something random']
这就是我试过的
Cov = pd.read_csv("path to CSV.csv", sep='||||', names = ["col 1", "col 2", "col 3"], engine = 'python')
它没有显示任何错误,但列没有拆分。
答案 0 :(得分:0)
将\
用于转义|
,因为特殊的正则表达式字符:
import pandas as pd
temp=u"""[u"ABC||||'ABCDadfasf||||'random something', 'another random']
[u"ABCD||||'ABCDadfasf||||'random somethingadf', 'another random adsd']
[u"ABDC||||'ABCDasdadfasf||||'random something random', 'another something random']"""
#after testing replace 'pd.compat.StringIO(temp)' to 'filename.csv'
df = pd.read_csv(pd.compat.StringIO(temp), sep=r"\|\|\|\|", names = ["col 1", "col 2", "col 3"], engine = 'python')
print (df)
col 1 col 2 col 3
0 [u"ABC 'ABCDadfasf 'random something', 'another random']
1 [u"ABCD 'ABCDadfasf 'random somethingadf', 'another random adsd']
2 [u"ABDC 'ABCDasdadfasf 'random something random', 'another something ...
#temp=u"""