我的应用程序包含抽屉导航器和堆栈导航器。但问题是,当我试图goback时,即使我是2-3堆深,它也会带我进入第一个屏幕。它不显示以前的屏幕,它总是把我带到主屏幕。下面是我的App.js代码
import React from 'react';
import {
ActivityIndicator,
AsyncStorage,
Button,
StatusBar,
StyleSheet,
View,
} from 'react-native';
import {StackNavigator, SwitchNavigator, DrawerNavigator} from 'react-navigation';
import Screen1 from './Screen/Screen1';
import Screen2 from './Screen/Screen2';
import Screen3 from './Screen/Screen3';
import Screen4 from './Screen/Screen4';
import Screen5 from './Screen/Screen5';
import ScreenList from './Screen/ScreenList';
import Login from './Screen/Login';
class AuthLoadingScreen extends React.Component {
constructor() {
super();
this._bootstrapAsync();
}
// Fetch the token from storage then navigate to our appropriate place
_bootstrapAsync = async () => {
const userToken = await AsyncStorage.getItem('user');
// This will switch to the App screen or Auth screen and this loading
// screen will be unmounted and thrown away.
this.props.navigation.navigate(userToken ? 'App' : 'Auth');
};
// Render any loading content that you like here
render() {
return (
<View style={styles.container}>
<ActivityIndicator/>
<StatusBar barStyle="default"/>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
alignItems: 'center',
justifyContent: 'center',
},
});
const AppStack = DrawerNavigator({
Screen1: { screen: Screen1},
Screen2: { screen: Screen2},
Screen3: { screen: Screen3},
Screen4: { screen: Screen4},
Screen5: { screen: Screen5},
ScreenList: { screen: ScreenList},
}, {contentComponent: SideBar});
const AuthStack = StackNavigator({Login: { screen: Login}},{headerMode:'none'});
const MyNavigator = SwitchNavigator(
{
AuthLoading: AuthLoadingScreen,
App: AppStack,
Auth: AuthStack,
},
{
initialRouteName: 'AuthLoading'
}
);
export default class App extends React.Component {
render() {
return <MyNavigator />;
}
}
从屏幕1,我点击按钮,然后转到屏幕2和屏幕3,如:
onPress={() => navigate('Screen2', { })}
它工作正常,但是当我使用屏幕3中的波纹管代码返回时,我需要屏幕1而不是屏幕2
this.props.navigation.goBack();
我错过了什么吗?
答案 0 :(得分:0)
你试过吗
1 - &gt; 2 - &gt; 3 - &gt; 4
<Button
onPress={() => goBack('3')}
title="Go to 3 screen"
/>