如何格式化json数组取决于我对api
请求json的条件这是我的前端json数组 我使用角度反应形式
创建了这个数组但Api需要而不是空字段
在上面的数组中是嵌套的days-＆gt; timings-＆gt; break
条件
1）如果天数不包含时间，则无需汇总（例如：第3天不包含时间，因此无需提交）
2）如果街区，楼层，房间都是空的，则无需登顶（例如：day [1] -timing [1]，timing [2]，day [2] -timing [2]）
3）如果休息是空的，则不需要在几天内提交休息数组（例如：day1 [1] - ＆gt;时间[3]，日[2] - ＆gt;时间[2]）
4
）如果mode为true（持续时间，数量），则为brets，如果mode为true （开始时间，结束时间是必需的
5）api不需要嵌套（只需要普通数组）（例如：[{}，{}，{}]）
通过上述条件，你可以假设这个数组
我尝试使用for循环来解决它，但它重复了不太好的事情
前端阵列
{
"startDate":"10-05-2018",
"endDate":"13-05-2018",
"days":[
{
"dayId":1,
"timings":[
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":1,
"floors":2,
"rooms":3,
"breaks":[
{
"type":1,
"mode":false,
"startTime":"01:00",
"endTime":"02:00",
"duration":1,
"quantity":1
},
{
"type":1,
"mode":true,
"startTime":"01:00",
"endTime":"02:00",
"duration":1,
"quantity":1
}
]
},
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":"",
"floors":"",
"rooms":"",
"breaks":[
{
"type":1,
"mode":false,
"startTime":"01:00",
"endTime":"02:00",
"duration":1,
"quantity":1
}
]
},
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":"",
"floors":"",
"rooms":"",
"breaks":[
]
},
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":2,
"floors":3,
"rooms":3,
"breaks":[
]
}
]
},
{
"dayId":2,
"timings":[
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":1,
"floors":2,
"rooms":3,
"breaks":[
{
"type":1,
"mode":true,
"startTime":"01:00",
"endTime":"02:00",
"duration":1,
"quantity":1
}
]
},
{
"startTime":"10:00",
"endTime":"12:00",
"cycle":1,
"blocks":"",
"floors":"",
"rooms":"",
"breaks":[
]
}
]
},
{
"dayId":3,
"timings":[
]
}
]
}
请求的数组
{
"start_date":"05-05-2018",
"end_date":"31-07-2018",
"branch_id":"2",
"day":[
{
"id":"1",
"start_time":"10:00",
"end_time":"12:00",
"breaks":[
{
"type":1,
"mode":false,
"duration":1,
"quantity":1
},
{
"type":1,
"mode":true,
"startTime":"01:00",
"endTime":"02:00",
}
],
"gen_repeat_cycle_id":"1",
"room_id":"1",
"floor_id":"2",
"block_id":"3"
},
{
"id":"1",
"start_time":"10:00",
"end_time":"12:00",
"breaks":[
{
"type":1,
"mode":false,
"duration":1,
"quantity":1
}
],
"gen_repeat_cycle_id":"2"
},
{
"id":"1",
"start_time":"10:00",
"end_time":"12:00",
"gen_repeat_cycle_id":"1"
},
{
"id":"1",
"start_time":"10:00",
"end_time":"12:00",
"gen_repeat_cycle_id":"1",
"room_id":"1",
"floor_id":"2",
"block_id":"3"
},
{
"id":"2",
"start_time":"10:00",
"end_time":"12:00",
"breaks":[
{
"type":1,
"mode":true,
"startTime":"01:00",
"endTime":"02:00",
}
],
"gen_repeat_cycle_id":"1",
"room_id":"1",
"floor_id":"2",
"block_id":"3"
},
{
"id":"2",
"start_time":"10:00",
"end_time":"12:00",
"gen_repeat_cycle_id":"1"
}
]
}
请帮帮我
答案 0 :(得分：2)
（更新） 这是我提出的解决方案
function processData(data) {
var newData = {};
newData.start_date = data.startDate;
newData.end_date = data.endDate;
newData.day = [];
for(var i = 0; i < data.days.length; i++) {
var currentDay = data.days[i];
for(var j = 0; j < currentDay.timings.length; j++) {
var currentTiming = currentDay.timings[j];
var newTimingObject = {};
newTimingObject.start_time = currentTiming.startTime;
newTimingObject.end_time = currentTiming.endTime;
newTimingObject.gen_repeat_cycle_id = currentTiming.cycle.toString();
newTimingObject.id = currentDay.dayId.toString();
if(currentTiming.breaks.length > 0) {
var currentBreaks = [];
for(var k = 0; k < currentTiming.breaks.length; k++) {
var newBreakObject = {};
newBreakObject.type = currentTiming.breaks[k].type;
newBreakObject.mode = currentTiming.breaks[k].mode;
if(currentTiming.breaks[k].mode === true) {
newBreakObject.startTime = currentTiming.breaks[k].startTime;
newBreakObject.endTime = currentTiming.breaks[k].endTime;
} else {
newBreakObject.duration = currentTiming.breaks[k].duration;
newBreakObject.quantity = currentTiming.breaks[k].quantity;
}
currentBreaks.push(newBreakObject);
}
newTimingObject.breaks = currentBreaks;
}
if(currentTiming.blocks !== '') {
newTimingObject.block_id = currentTiming.blocks.toString();
}
if(currentTiming.floors !== '') {
newTimingObject.floor_id = currentTiming.floors.toString();
}
if(currentTiming.rooms !== '') {
newTimingObject.room_id = currentTiming.rooms.toString();
}
newData.day.push(newTimingObject);
}
}
return newData;
}
我在jsfiddle中有解决方案检查出来，我不理解所请求数组中的branch_id。