我找到了关于比较两个数组的不同答案,但在我的情况下没有一个工作。我有两个Jsons,Old.json保存旧值,New.json保存新值。我只想在Old中保存New.json中的新功能,而我在Old.json中还没有这个功能
OLD.JSON
{
"jogos-da-copa": [
"/videos/291856.html",
"/videos/291830.html",
"/videos/291792.html",
"/videos/291759.html",
"/videos/291720.html",
"/videos/291705.html"
],
"apresentacao": [
"/videos/2926328.html",
"/videos/67.html",
"/videos/36.html",
"/videos/3.html"
]
}
NEW.JSON
{
"jogos-da-copa": [
"/videos/291887.html",
"/videos/291856.html",
"/videos/291830.html",
"/videos/291792.html",
"/videos/291759.html",
"/videos/291720.html",
"/videos/291705.html"
],
"apresentacao": [
"/videos/2926385.html",
"/videos/2926328.html",
"/videos/67.html",
"/videos/36.html",
"/videos/3.html"
]
}
我使用了这段代码,但没有显示差异
$old1 = json_decode(file_get_contents('old.json'), true);
$new2 = json_decode(file_get_contents('new.json'), true);
$test = [];
foreach ($old1 as $key1 => $olds1) {
foreach ($new2 as $key2 => $news2 ) {
$test[] = array_diff($olds1, $news2);
}
}
var_dump($test);
答案 0 :(得分:1)
请使用以下功能并将旧的和新的数组传递给参数
$old = json_decode($old_json, true);
$new = json_decode($new_json, true);
$array_keys = array_keys( array_merge( $old, $new));
$dif_array = array();
foreach($array_keys as $key)
{
if(array_key_exists($key, $old) && array_diff($new[$key], $old[$key])){
$dif_array[$key] = array_diff($new[$key], $old[$key]);
} else {
$dif_array[$key] = $new[$key];
}
}
$final_array = array_merge_recursive($old, $dif_array);
答案 1 :(得分:0)
来自array_diff docs:
将array1与一个或多个其他数组进行比较,并返回array1中任何其他数组中不存在的值。
在您的情况下,新数组包含旧数组中的所有值。要获取所有新值的列表,您需要切换参数:
$old1 = json_decode(file_get_contents('old.json'), true);
$new2 = json_decode(file_get_contents('new.json'), true);
$test = [];
foreach ($old1 as $key1 => $olds1) {
foreach ($new2 as $key2 => $news2 ) {
$test[] = array_diff($news2, $olds1);
}
}
var_dump($test);