Question

我有以下列表：

theList= ["ABCD","EFGH","IJKL","MNOP"]

我想将此列表写入CSV文件，作为单行中每列中的不同元素。最终的CSV文件应如下所示;

  -----------------------------
1 | ABCD | EFGH | IJKL | MNOP |
  -----------------------------

我尝试了以下代码（使用csv库），但它写入多行而不是列

tempRows = zip(theList)
    with open("Final.csv", 'w', newline='', encoding="utf8") as f:
        writer = csv.writer(f, delimiter=',')
        for tempRow in tempRows:
            writer.writerow(tempRow)

Answer 1

您是否尝试将参数列表直接传递给writerow？

writer.writerow(theList)

Answer 2

为什么要调用zip然后迭代它？只需用writerow直接致电theList即可。

with open("Final.csv", 'w', newline='', encoding="utf8") as f:
    writer = csv.writer(f, delimiter=',')
    writer.writerow(theList)

Answer 3

如果将每个项目放入列表中的列表中，则可以写入单行：

theList= ["ABCD","EFGH","IJKL","MNOP"]
theList = [[string for string in theList]]
out_file = r"E:\data\one_line.csv"

with open(out_file, "w", newline="") as data:
writer = csv.writer(data)
for sub_list in theList:
    writer.writerow(sub_list)

使用Python将列表写入CSV文件中的列

3 个答案: