Question

我正在尝试混合两个多维数组，因此列表可以用所有可能的对来表示。例如，属于特定联盟(Bundesliga or La Liga)的玩家可以在这些团队(Bayern Munich, Real Madrid, Or FC Barcelona)中玩，而拥有此(*)的玩家可以在所有团队中玩。这是两个阵列：

String[,] leaguePairs = new String[3, 2] { { "Bayern Munich", "Bundesliga" }, { "Real Madrid", "La Liga" }, { "FC Barcelona", "La Liga" } };
String[,] playerPairs = new String[4, 2] { { "Player-1", "Bundesliga" }, { "Player-2", "La Liga" }, { "Player-3", "La Liga" }, { "Player-4", "*" } };

输出：

[Player-2, Real Madrid],
[Player-2, FC Barcelona],
[Player-1, Bayern Munich],
[Player-4, Real Madrid],
[Player-4, FC Barcelona],
[Player-4, Bayern Munich]

我如何表示该输出？非常感谢你们的帮助！

Answer 1

另一种方法是创建一个查找和可用团队列表，然后使用这些东西来创建你想要的列表

var leaguePairs = new String[3, 2] { { "Bayern Munich", "Bundesliga" }, { "Real Madrid", "La Liga" }, { "FC Barcelona", "La Liga" } };
var playerPairs = new String[4, 2] { { "Player-1", "Bundesliga" }, { "Player-2", "La Liga" }, { "Player-3", "La Liga" }, { "Player-4", "*" } };

var lookup = Enumerable.Range(0, leaguePairs.GetLength(0))
                       .Select(row =>
                                     new {
                                            Key = leaguePairs[row, 1],
                                            Value = leaguePairs[row, 0]
                                         })
                       .ToLookup(x => x.Key, 
                                 x => x.Value);

var teams = Enumerable.Range(0, leaguePairs.GetLength(0))
                      .Select(row => leaguePairs[row, 0])
                      .ToHashSet();

var list = Enumerable.Range(0, playerPairs.GetLength(0))
                     .SelectMany(row =>  
                                 playerPairs[row, 1] == "*" 
                                 ? 
                                 teams.Select(team => 
                                       new { 
                                           Name = playerPairs[row, 0], 
                                           Team = team 
                                      })
                                      .ToList()
                                  : 
                                  lookup[playerPairs[row, 1]]
                                  .Select(team => 
                                     new { 
                                          Name = playerPairs[row, 0], 
                                          Team = team 
                                     })
                                   .ToList()
                      ).ToList();

Answer 2

此代码应该有效。

String[,] leaguePairs = new String[3, 2] { { "Bayern Munich", "Bundesliga" }, { "Real Madrid", "La Liga" }, { "FC Barcelona", "La Liga" } };
String[,] playerPairs = new String[4, 2] { { "Player-1", "Bundesliga" }, { "Player-2", "La Liga" }, { "Player-3", "La Liga" }, { "Player-4", "*" } };

for (var i = 0; i < leaguePairs.GetLength(0); i++)
{
  for (var j = 0; j < playerPairs.GetLength(0); j++)
   {
    if (Equals(playerPairs[j, 1], leaguePairs[i, 1]) || Equals(playerPairs[j, 1], "*"))
   {
     Console.WriteLine($@"[{playerPairs[j, 0]}, {leaguePairs[i, 0]}]");
    }
  }
}

编辑：（2018/5/9 9:58）

这是您想要的方法。

public String[,] MatchPlayers(String[,] leaguePairs, String[,] playerPairs)
    {
        var results = new List<(string, string)>();
        for (var i = 0; i < leaguePairs.GetLength(0); i++)
        {
            for (var j = 0; j < playerPairs.GetLength(0); j++)
            {
                if (Equals(playerPairs[j, 1], leaguePairs[i, 1]) || Equals(playerPairs[j, 1], "*"))
                {
                    results.Add((playerPairs[j, 0], leaguePairs[i, 0]);
                }
            }
        }

        var stringArray = new String[results.Count, 2];
        for (var i = 0; i < results.Count; i++)
        {
            var result = results[i];
            stringArray[i, 0] = result.Item1;
            stringArray[i, 1] = result.Item2;
        }

        return stringArray;
    }

如何表示多维数组字符串的所有可能对[，]

2 个答案: