我的模型(示例)如下:
KeyError: '_module'
我的JPA定义:
CREATE TABLE person (
id INT PRIMARY KEY,
name TEXT
...
);
CREATE TABLE team (
id INT PRIMARY KEY,
name TEXT
....
);
CREATE TABLE team_reference_persons (
team_id INT NOT NULL,
person_id INT NOT NULL,
uses_telephone BOOLEAN,
PRIMARY KEY (team_id, person_id),
FOREIGN KEY (team_id) REFERENCES team(id),
FOREIGN KEY (person_id) REFERENCES person(id)
);
到目前为止,非常好,当你需要的只是团队中的人员名单时。但是现在我需要在我的人域中添加联接表中的@Entity
@Table(name = "team")
public class Team {
@Id
private Integer id;
@OneToMany
@JoinTable(name = "team_reference_persons", joinColumns = @JoinColumn(name = "team_id", referencedColumnName = "id"), inverseJoinColumns = @JoinColumn(name = "person_id", referencedColumnName = "id"))
private List<Person> teamReferencePersons;
...
}
@Entity
@Table(name = "person")
public class Person {
@Id
private UUID id;
private String name;
...
}
属性,所以我正在寻找一种方法来保持人员的逻辑,同时我创建了一个新的子类。
team_reference_persons.uses_telephone
然后按private class TeamIndividual extends Person {
boolean uses_telephone;
}
更改List<Person>
实体上的Team
。这有可能吗?应该以如此聪明的方式指示JPA,它将连接表属性添加到最终目标实体(在读取和保存时)。
答案 0 :(得分:1)