Question

public class Player
{
    private string Name;
    private int Health = 100;
    private int Damage;

    public Player(string name, int health, int damage)
    {
        name = Name;
        health = Health;
        damage = Damage;
    }        
}

public class Enemy
{
    public void enemyTakeDamage()
    {
        int takenDamage;            
    }

    private string Name;
    private int Health = 100;
    private int Damage;
    public string enemyMessages;

    public Enemy(string name, int health, int damage)
    {
        name = Name;
        health = Health;
        damage = Damage;
    }        
}

class Program
{
    static void Main(string[] args)
    {
        bool dead;
        Player P1 = new Player("Zach", 100, 20);               
    }            
}

所以我初始化了一个名为P1的对象，其名称为＆＃34; zach＆＃34;并且hp为100且损坏为20，我无法在其他地方访问这3个变量。这些不是播放器类中的私有变量，我在谈论类中通过执行初始化的那些：

public Player(string name, int health, int damage)

我想我可以在任何我想要的地方打电话给P1.health吗？感谢任何帮助，这是我的第一个基于文本的控制台游戏我正在努力，所以其他输入也很感激。

Answer 1

如果您想要覆盖p1.Health等属性/字段，则必须公开更改。

其次，您的作业顺序错误。

第三，您可以访问p1.Health而不是p1.health，因为Player没有名称为health的属性/字段。它是构造函数的参数名称

public class Player
{
    public string Name;
    public int Health = 100;
    public int Damage;

    /* II. way
          public string Name {get;set;}
          public int Health {get;set;} = 100;
          public int Damage {get;set;}
      */

    /* III. way
        private string _name;
        private int _health = 100;
        private int _damage;

        public string Name {get { return _name ; } }
    */

    public Player(string name, int health, int damage)
    {
        Name = name;
        Health = health;
        Damage = damage;
    }
}

public class Enemy
{
    public void enemyTakeDamage()
    {
        int takenDamage;
    }

    private string Name;
    private int Health = 100;
    private int Damage;
    public string enemyMessages;

    public Enemy(string name, int health, int damage)
    {
        Name = name;
        Health = health;
        Damage = damage;
    }
}


public class Program
{
    static void Main(string[] args)
    {
        bool dead;
        Player P1 = new Player("Zach", 100, 20);
        Console.WriteLine("Name : " + P1.Name + Environment.NewLine +
                          "Health : " + P1.Health +Environment.NewLine +
                          "Damage : "+ P1.Damage);

        Console.ReadKey();
    }

    /* static player
    public static Player P1;
    static void Main(string[] args)
    {
       bool dead;
       P1 = new Player("Zach", 100, 20);
       Console.WriteLine("Name : " + P1.Name + Environment.NewLine +
                         "Health : " + P1.Health + Environment.NewLine +
                         "Damage : " + P1.Damage);

       Console.ReadKey();
    }
   */
}

Answer 2

查看所有内容，以下是我认为您的定义：

"jest": {
    "moduleFileExtensions": [
      "js",
      "json",
      "vue"
    ],
    "transform": {
      ".*\\.(vue)$": "<rootDir>/node_modules/vue-jest",
      "^.+\\.js$": "<rootDir>/node_modules/babel-jest"
    },
    "snapshotSerializers": [
      "<rootDir>/node_modules/jest-serializer-vue"
    ],
    "moduleNameMapper": {
      "^@/(.*)$": "<rootDir>/src/$1"
    }
  }

假设伤害是角色所造成的伤害，那么这应该作为战斗模型。你可以分别改变对Player.DoDamage（Enemy e）和Enemy.DoDamage（Player p）的Do and Take Damage。

不能调用类的实例变量？

2 个答案: