Question

我是python的新手，并且当我使用name.isalnum方法时，代码将在下面的简单程序有一个小问题它只适用于第一个工作，例如如果我运行程序并输入名称1joe，if语句将运行，但如果我要输入Joe 1jacques，if语句将忽略我输入中的数字并继续正常，任何人都知道问题？

def main():
    print ("WELCOME")
    name = input("Please Enter your name ")
    if name.isdigit():
        print ("Name only includes numbers, name can only have letters: ")
        name = input("Reenter Name:" )
    elif name.isalnum():
        print ("Name can only include letters : ")
        name = input("Reenter Name: ")
    elif len(name) ==0:
        print ("Name field is empty")
        name= input("Reenter name:" )
    print ("Nice to meet you! " + name)
    print (len(name))

This is me running the program with both sets on inputs

Answer 1

忽略

isalnum，因为您输入的字符串中有空格。使用str.replace删除空格，然后使用isalnum

<强>实施例

def main():
    print ("WELCOME")
    name = input("Please Enter your name ")
    if name.isdigit():
        print ("Name only includes numbers, name can only have letters: ")
        name = input("Reenter Name:" )
    elif name.replace(' ','').isalnum():   #-->Update
        print ("Name can only include letters : ")
        name = input("Reenter Name: ")
    elif len(name) ==0:
        print ("Name field is empty")
        name= input("Reenter name:" )
    print ("Nice to meet you! " + name)
    print (len(name))

基本Python：错误检查.isdigit，.isalnum

1 个答案: